What’s the area and the perimeter and of the triangle?

4 quarters are equal in value to 10 dimes.

bija089 [108]

Answer:

Step-by-step explanation:

7 0

4 years ago

katie pays $725 a month for rent, $40 for cable and $3.60 an hour for local telephone service. if his monthly expenditures last

Nuetrik [128]

The answer would be: He spent 17 hours on the phone
Explanation: $826.20 - $725= $101.2 - $40= $61.12 / $3.60= 17hrs

8 0

3 years ago

Given the piecewise function. Shown below

creativ13 [48]

Answer:

(x, g(x)) = {(-2, -2), (0, 0), (2, 2), (4, -3), (6, -3)}

Step-by-step explanation:

The first three values of x in the table are all less than or equal to 2, so the first part of the function definition applies. The y-value is equal to the x-value. The ordered pairs are ...

(-2, -2), (0, 0), (2, 2)

The last two values of x in the table are more than 2, so the last part of the function definition applies. For those values of x, the y-value is -3. The ordered pairs are ...

(4, -3), (6, -3)

5 0

3 years ago

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is N (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

(c) The value of $P(\bar X\geq 69.1)$ is 0.3670.

Step-by-step explanation:

A random sample of size n = 10 is selected from a population.

Let the population be made up of the random variable X.

The mean and standard deviation of X are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. n = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$