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3 years ago

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An older person is 4 years older than 7 times the age of a younger person. The sum of their ages is 44. Find their ages

1 answer:

Fynjy0 [20]3 years ago

8 0

Answer:

5 yr and 39 yr

Step-by-step explanation:

Let x = the age of the younger

then 7x + 4 = the age of the older

Now x + 7x + 4 = 44

8x + 4 = 44

8x = 40

x = 5

7x + 4 = 7(5) + 4 = 35 + 4 = 39

Check: 5 + 39 = 44

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A. - 8/5<br><br>B. 5/8<br><br>C. - 5/8 <br><br>D. 8/5

IrinaK [193]

Answer:

5/8

Step-by-step explanation:

To find the slope, use the formula

m = (y2-y1)/(x2-x1)

= (2 - -3)/(6 - -2)

= (2+3)/(6+2)

= 5/8

5 0

3 years ago

Repeat the following procedure for the four given numbers .

Volgvan

3
multiply by 4
12
add 12
24
divide by 2
12
subtract 6
6

number 6 : 6(4) = 24... + 12 = 36...36/2 = 18.....- 6 = 12
number 8 : 8(4) = 32....+ 12 = 44...44/2 = 22....- 6 = 16
number 12: 12(4) = 48....+ 12 = 60...60/2 = 30....-6 = 24

well...by following these steps, it appears the original number doubles as a result.

4 0

4 years ago

Read 2 more answers

What is the fraction for .50

Pavel [41]

The fraction for .50 is (1/2)

6 0

4 years ago

Read 2 more answers

4x2 is the GCF of this polynomial.

viva [34]

Answer:

Correct option is B

Step-by-step explanation:

Note that

$20x^2y=2\cdot 2\cdot 5\cdot x\cdot x\cdot y,$

$56x^3=2\cdot 2\cdot 2\cdot 7\cdot x\cdot x\cdot x.$

If the mystery term is $22x^3=2\cdot 11\cdot x\cdot x\cdot x,$ then the

$GCF(20x^2y,56x^3,22x^3)=2\cdot x\cdot x=2x^2.$

If the mysteyr term is $24x^2y=2\cdot 2\cdot 2\cdot 3\cdot x\cdot x\cdot y,$ then

$GCF(20x^2y,56x^3,24x^2y)=2\cdot 2\cdot x\cdot x=4x^2.$

If the mysteyr term is $26x^2y=2\cdot 13\cdot x\cdot x\cdot y,$ then

$GCF(20x^2y,56x^3,26x^2y)=2\cdot x\cdot x=2x^2.$

If the mysteyr term is $28y^3=2\cdot 2\cdot 7\cdot y\cdot y\cdot y,$ then

$GCF(20x^2y,56x^3,28y^3)=2\cdot 2=4.$

Thus, correct option is B

8 0

3 years ago

Read 2 more answers

Find the value of each of the following polynomial:

VLD [36.1K]

Answer:

Step-by-step explanation:

( i )

$p(x) = 4x^2 -3x + 7\\\\p(1) = 4(1)^2 - 3(1) + 7 = 4 - 3 + 7 = 1 + 7 = 8$

( ii)

$q(y) = 2y ^3 -4y + \sqrt{11}\\\\q(1) = 2( 1)^3 - 4(1) + \sqrt{11} = 2 - 4 + \sqrt{11} = -2 + \sqrt{11}$

(iii)

$r(t) = 4t^4 + 3t^3 -t^2+6\\\\r(p) = 4(p)^4 + 3(p)^3 - (p)^2 + 6= 4p^4 + 3p^3 -p^2 + 6$

(iv)

$s(z) = z^3 -1\\s(1) = (1)^3 -1 = 1 - 1 = 0$

(v)

$p(x) = 3x^2+5x-7 \\\\p(1) = 3(1)^2 + 5(1) - 7 = 3 + 5 - 7 = 8 - 7 = 1$

(vi)

$q(z) =5z^3 -4z +\sqrt{2}\\\\q(2) = 5(2)^3 - 4(2) \sqrt2 = (5 \times 8) - ( 4 \times 2) + \sqrt 2 = 40 - 8 + \sqrt 2 = 32 + \sqrt2$

7 0

3 years ago

Read 2 more answers