You read it from left to right the value of 2 is two thousands or 2,000 then the second 2 is 200 and ect.
All you have to do is take the square root of 363=11√3
11√3-3√27
No.
The only value that can be put in K that would have the same zeros would be 4 but 4 is not an odd integer. If there was an odd integer that the sum and product would be the same then it would lie on the x-axis. but only 4 fits the criteria.
<h3>6 is a solution to equation 6x + 5 = 12 + 5x</h3>
<em><u>Solution:</u></em>
<em><u>Given equation is:</u></em>
6x + 5 = 12 + 5x
Try the numbers 4, 5, 6, 7 in the equation to test whether any of them is a solution
<em><u>Substitute x = 4</u></em>
6(4) + 5 = 12 + 5(4)
24 +5 = 12 + 20

Thus 4 is not a solution
<em><u>Substitute x = 5</u></em>
6(5) + 5 = 12 + 5(5)
30 + 5 = 12 + 25

Thus 5 is not a solution
<em><u>Substitute x = 6</u></em>
6(6) + 5 = 12 + 5(6)
36 + 5 = 12 + 30

Thus 6 is not a solution
<em><u>Substitute x = 7</u></em>
6(7) + 5 = 12 + 5(7)
42 + 5 = 12 + 35
47 = 47
Thus 6 is a solution