Answer: 234
Step-by-step explanation:
A golden rectangle is a rectangle whose length is approximately 1.6 times its width.
Mike Hallahan would like to plant a rectangular garden in the shape of a golden rectangle.
If he has "234"* feet of fencing is available, find the dimensions of the garden. *Makes more sense.
:
let w = the width of the garden
then
1.6w = the length
:
2(1.6w) + 2w = 234
3.2w + 2w = 234
5.2w = 234
w = 234/5.2
w = 45 ft is the width
and
1.6(45) = 72 ft is the length
:
:
Check
2(72) + 2(45) =
144 + 90 = 234
Answer:
x = 16
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
(x+2) * 2 = 6^2
2(x+2) = 36
Divide each side by 2
x+2 = 18
Subtract 2
x+2-2 = 18-2
x = 16
<u>Answer:</u>
P(A') = 0.75
<u>Step-by-step explanation:</u>
We are given that the probability P(A) = 0.25 and we are to determine the probability of the complement of A.
According to the Complement Rule of any probability, the sum of the probabilities of an event and its complement must be equal to 1.
So for for the event A,
P(A) + P(A') = 1
0.25 + P(A') = 1
P(A') = 1 - 0.25
P(A') = 0.75
9514 1404 393
Answer:
(a) cannot be determined
(b) 44 cm^2
(c) 87 m^2
(d) 180 m^2
(e) 132 m^2
Step-by-step explanation:
(a) missing a horizontal dimension
__
(b) The difference between the bounding rectangle and the lower-left cutout is ...
(8 cm)(7 cm) -(3 cm)(4 cm) = (56 -12) cm^2 = 44 cm^2
__
(c) The difference between the bounding rectangle and the center cutout is ...
(13 m)(7 m) -(4 m)(1 m) = (91 -4) m^2 = 87 m^2
__
(d) The difference between the bounding rectangle and the two cutouts is ...
(20 m)(25 m) -(16 m)(20 m) = (20 m)(25 -16) m = (20 m)(9 m) = 180 m^2
__
(e) The difference between the bounding rectangle and the two cutouts is ...
(14 m)(12 m) -(12 m)(3 m) = (12 m)(14 -3) m = (12 m)(11 m) = 132 m^2
Answer:

Step-by-step explanation:
<u>Quadratic Function</u>
The quadratic function can be expressed in the following form:

Where a is a real number different from 0, and x1, x2 are the roots or zeroes of the function.
From the conditions stated in the problem, we know
x_1=1+\sqrt{2}, \ x_1=1-\sqrt{2}
Substitute in the general formula above:
![y=a[x-(1+\sqrt{2})][x-(1-\sqrt{2})]](https://tex.z-dn.net/?f=y%3Da%5Bx-%281%2B%5Csqrt%7B2%7D%29%5D%5Bx-%281-%5Csqrt%7B2%7D%29%5D)
Operate the indicated product

To find the value of a, we use the y-intercept which is the value of y when x=0, thus

It follows that

Thus, the required quadratic function is

Or, equivalently
