Question

In triangle ABC, c = 9 m/_B = 65° and a = 105. Find b.​

Answer 1

Answer:

b = 101.52

Step-by-step explanation:

b^2 = a^2 + c^2 - 2ac CosB

b^2 = 105^2 + 9^2 - 2(105)(9) Cos 65°

b^2 = 11 106 - 798.75

b^2 = 10 307.25

b = 101.52

Answer 2

Answer:101.52

Step-by-step explanation:

Given

a=105

c=9

$B=65^{\circ}$

using cosine rule

$2acCosB=a^2+c^2-b^2$

$2(105)(9)Cos65=105^2+9^2-b^2$

$b^2=11025+81-798.7485$

b=101.524