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Olin [163]
3 years ago
8

In triangle ABC, c = 9 m/_B = 65° and a = 105. Find b.​

Mathematics
2 answers:
tresset_1 [31]3 years ago
5 0

Answer:

b = 101.52

Step-by-step explanation:

b^2 = a^2 + c^2 - 2ac CosB

b^2 = 105^2 + 9^2 - 2(105)(9) Cos 65°

b^2 = 11 106 - 798.75

b^2 = 10 307.25

b = 101.52

garik1379 [7]3 years ago
3 0

Answer:101.52

Step-by-step explanation:

Given

a=105

c=9

B=65^{\circ}

using cosine rule

2acCosB=a^2+c^2-b^2

2(105)(9)Cos65=105^2+9^2-b^2

b^2=11025+81-798.7485

b=101.524

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Add.
Sidana [21]

Answer:

1\frac{7}{20}

Step-by-step explanation:

1. Convert the mixed number to an improper fraction to match the rest of the problem (this just makes it easier for now, the answer will still be a mixed number)

-1\frac{4}{5} becomes \frac{9}{5}

2. Re-write the new equation. When there is a "+" in front of a set of parentheses the expression doesn't change aside from removing the plus signs.

The new equation becomes

\frac{9}{5} - \frac{1}{4} -\frac{1}{5}

3. Calculate. Just work out the new expression.

The answer is \frac{27}{20}

4. Convert to a simplified mixed decimal.

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2 years ago
What is the multiplicative inverse of 10/3?
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The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
BabaBlast [244]

Step-by-step explanation:

the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).

I think your teacher made a mistake, or you made one when typing the question in here.

there is no factor r that creates

15×r = 9

and

9×r = 5/27

it would mean that

15 × r² = 5/27

r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81

r = 1/9

but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9

and 9 × 1/9 = 9/9 = 1 is NOT 5/27

so, this can't be right.

on the other hand

15 × r = 9

r = 9/15 = 3/5

and then

9 × 3/5 = 27/5

so, either the sequence should have been

15, 5/3, 5/27

or (and I suspect this to be true)

15, 9, 27/5

under that assumption we have

s1 = 15

r = 3/5

sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)

s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =

= 3 × 19683/390625 = 59049/390625 =

= 0.15116544 ≈ 0.151

6 0
2 years ago
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