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Olin [163]
3 years ago
8

In triangle ABC, c = 9 m/_B = 65° and a = 105. Find b.​

Mathematics
2 answers:
tresset_1 [31]3 years ago
5 0

Answer:

b = 101.52

Step-by-step explanation:

b^2 = a^2 + c^2 - 2ac CosB

b^2 = 105^2 + 9^2 - 2(105)(9) Cos 65°

b^2 = 11 106 - 798.75

b^2 = 10 307.25

b = 101.52

garik1379 [7]3 years ago
3 0

Answer:101.52

Step-by-step explanation:

Given

a=105

c=9

B=65^{\circ}

using cosine rule

2acCosB=a^2+c^2-b^2

2(105)(9)Cos65=105^2+9^2-b^2

b^2=11025+81-798.7485

b=101.524

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a. Find the graph of their common region in the attachment

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<h3>a. How to sketch the region common to the graphs?</h3>

Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.

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So, the graph of x + y ≤ 6 is the region below the line y = - x + 6

From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)

Find the graph of their common region in the attachment

<h3>b. The area of the common region</h3>

From the graph, we see that the common region is a right angled triangle with

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So, its area = 1/2 × height × base

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= 1/2 × 16 units²

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So, the area of the common region of the graphs is 8 units²

Learn more about region common to graphs here:

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