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blondinia [14]
3 years ago
7

Assume a random sample of size n is from a normal population. Assume a single sample t test is used to for hypothesis testing. T

he null hypothesis is that the population mean is zero versus the alternative hypothesis that it is not zero. If the sample size is decreased, and the Type I error rate is unchanged, then the Type II error rate will increase. A. True B. False
Mathematics
1 answer:
valentinak56 [21]3 years ago
5 0

Answer:

True

Step-by-step explanation:

Type I and Type II are not independent of each other - as one increases, the other decreases.

However, increases in N cause both to decrease, since sampling error is reduced.

A small sample size might lead to frequent Type II errors, i.e. it could be that your (alternative) hypotheses are right, but because your sample is so small, you fail to reject the null even though you should.

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A sample of final exam scores is normally distributed with a mean equal to 23 and a variance equal to 16. Part (a) What percenta
deff fn [24]

Answer:

Let X = score of final exam.

X~normal(23, 16)

(a)

percentage of score between 19 and 27

= P(19 < X < 27)

= P((19-23) / sqrt(16) < Z < (27 - 23) / sqrt(16))

= P(-1 < Z < 1)

= 1 - P(Z <= -1) - P(Z >= 1)

= 1 - P(Z >= 1) - P(Z >= 1)

= 1 - 2*P(Z >= 1)

= 1 - 2(0.1587)

= 0.6826

= 68.26%

According to Normal Distribution Table

P(Z>=1) = 1 - P(Z<1) = 1-0.8413

So the final percentage is 68.26%

7 0
4 years ago
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Yuri [45]
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8 0
3 years ago
Find the number of permutation of all the letters of the word "MULTIPLY".​
olga_2 [115]

Answer:

The answer is 40 320 ways.

Step-by-step explanation:

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So for this question, MULTIPLY can be arranged in many forms :

8P8 = 40 320

7 0
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garik1379 [7]

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6 0
3 years ago
Please solve for x!!
kaheart [24]

Answer:

See below, please!

Step-by-step explanation:

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Hope this helped!

7 0
3 years ago
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