Answer:
![\frac{18}{32}>\frac{16}{32}](https://tex.z-dn.net/?f=%5Cfrac%7B18%7D%7B32%7D%3E%5Cfrac%7B16%7D%7B32%7D)
Step-by-step explanation:
We need to find which statements are true.
Solution to find the same we will solve each statement and will conclude the same.
1. ![\frac{14}{21}>\frac{17}{24}](https://tex.z-dn.net/?f=%5Cfrac%7B14%7D%7B21%7D%3E%5Cfrac%7B17%7D%7B24%7D)
Now On solving we get;
![\frac{14}{21} = 0.66](https://tex.z-dn.net/?f=%5Cfrac%7B14%7D%7B21%7D%20%3D%200.66)
![\frac{17}{24}=0.70](https://tex.z-dn.net/?f=%5Cfrac%7B17%7D%7B24%7D%3D0.70)
So we can see that 0.70 > 0.66
Hence The given statement is False.
2. ![\frac{18}{32}>\frac{16}{32}](https://tex.z-dn.net/?f=%5Cfrac%7B18%7D%7B32%7D%3E%5Cfrac%7B16%7D%7B32%7D)
Now On solving we get;
![\frac{18}{32}=0.5625](https://tex.z-dn.net/?f=%5Cfrac%7B18%7D%7B32%7D%3D0.5625)
![\frac{16}{32}= 0.5](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B32%7D%3D%200.5)
So we can see that 0.5625 > 0.5
Hence The given statement is True.
3. ![\frac{20}{15}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B15%7D%3C%5Cfrac%7B28%7D%7B23%7D)
Now On solving we get;
![\frac{20}{15} = 1.33](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B15%7D%20%3D%201.33)
![\frac{28}{23}=1.2](https://tex.z-dn.net/?f=%5Cfrac%7B28%7D%7B23%7D%3D1.2)
So we can see that 1.33 > 1.2
Hence The given statement is False.
4. ![\frac{29}{35}](https://tex.z-dn.net/?f=%5Cfrac%7B29%7D%7B35%7D%3C%5Cfrac%7B20%7D%7B30%7D)
Now On solving we get;
![\frac{29}{35}= 0.82](https://tex.z-dn.net/?f=%5Cfrac%7B29%7D%7B35%7D%3D%200.82)
![\frac{20}{30}= 0.66](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B30%7D%3D%200.66)
So we can see that 0.82 > 0.66
Hence The given statement is False.
Answer:
1. We assume, that the number 33.39 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 33.39 is 100%, so we can write it down as 33.39=100%.
4. We know, that x is 13% of the output value, so we can write it down as x=13%.
5. Now we have two simple equations:
1) 33.39=100%
2) x=13%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
33.39/x=100%/13%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 13% of 33.39
33.39/x=100/13
(33.39/x)*x=(100/13)*x - we multiply both sides of the equation by x
33.39=7.6923076923077*x - we divide both sides of the equation by (7.6923076923077) to get x
33.39/7.6923076923077=x
4.3407=x
x=4.3407
now we have:
13% of 33.39=4.3407
Step-by-step explanation:
91.5 is the perimeter. It's just 5a.
Answer:
a)yes
Step-by-step explanation:
5 times 5 is 25
8 times 5 is 40
Answer:
![DC=\frac{8}{3}\ units](https://tex.z-dn.net/?f=DC%3D%5Cfrac%7B8%7D%7B3%7D%5C%20units)
Step-by-step explanation:
The picture of the question in the attached figure
we know that
The triangle ABD is an isosceles triangle
because
AB=BD
The segment BM is a perpendicular bisector segment AD
so
<em>In the right triangle ABM</em>
Applying the Pythagorean Theorem
![BM^2=AB^2-AM^2](https://tex.z-dn.net/?f=BM%5E2%3DAB%5E2-AM%5E2)
we have
![AB=5\ units\\AM=x\ units](https://tex.z-dn.net/?f=AB%3D5%5C%20units%5C%5CAM%3Dx%5C%20units)
substitute
![BM^2=5^2-x^2](https://tex.z-dn.net/?f=BM%5E2%3D5%5E2-x%5E2)
-----> equation A
<em>In the right triangle BMC</em>
Applying the Pythagorean Theorem
![BM^2=BC^2-MC^2](https://tex.z-dn.net/?f=BM%5E2%3DBC%5E2-MC%5E2)
we have
![BC=7\ units\\MC=AC-AM=(9-x)\ units](https://tex.z-dn.net/?f=BC%3D7%5C%20units%5C%5CMC%3DAC-AM%3D%289-x%29%5C%20units)
substitute
![BM^2=7^2-(9-x)^2](https://tex.z-dn.net/?f=BM%5E2%3D7%5E2-%289-x%29%5E2)
![BM^2=49-81+18x-x^2](https://tex.z-dn.net/?f=BM%5E2%3D49-81%2B18x-x%5E2)
----> equation B
equate equation A and equation B
![-x^2+18x-32=25-x^2](https://tex.z-dn.net/?f=-x%5E2%2B18x-32%3D25-x%5E2)
solve for x
![18x=25+32\\18x=57\\\\x=\frac{57}{18}](https://tex.z-dn.net/?f=18x%3D25%2B32%5C%5C18x%3D57%5C%5C%5C%5Cx%3D%5Cfrac%7B57%7D%7B18%7D)
Simplify
![x=\frac{19}{6}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B19%7D%7B6%7D)
<em>Find the length of DC</em>
![DC=AC-2x](https://tex.z-dn.net/?f=DC%3DAC-2x)
substitute the given values
![DC=9-2(\frac{19}{6})](https://tex.z-dn.net/?f=DC%3D9-2%28%5Cfrac%7B19%7D%7B6%7D%29)
![DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units](https://tex.z-dn.net/?f=DC%3D9-%5Cfrac%7B19%7D%7B3%7D%5C%5C%5C%5CDC%3D%5Cfrac%7B8%7D%7B3%7D%5C%20units)