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Soloha48 [4]
2 years ago
7

Describe the difference between an exothermic and endothermic process in terms of a chemical compound or reaction.

Chemistry
1 answer:
Elza [17]2 years ago
7 0

exo releases energy endo absorbs

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an acid accepts H and removes them from a solution, is a solution where the water molecules are intact
n200080 [17]
<h3>An acid accepts H and removes them from a solution</h3>

When placed in water, acids, bases, and salts dissociate (separate) into electrolytes (ions). Salts dissociate into a cation (that is not H+) and an anion (that is not OH-), whereas acids and bases dissociate into H+ and an anion. An acid separates into anions and hydrogen ions (H+). Strong acids produce a high concentration of H+ by dissociating every single one of their molecules . Water-based solutions,

Acid:

When a material or chemical is in solution, it releases hydrogen ions (H+), which are known as acids. All hydrogen ions (H+) and chloride ions (Cl-), which are normally bound together by ionic bonding, dissociate (separate) in water when exposed to a strong acid like hydrochloric acid (HCl). Only some ions disintegrate into hydrogen ions (H+) and bicarbonate ions (HCO3-) in a weak acid like carbonic acid (H2CO3), while others are still bound together by ionic bonds.

Define base?

A base is a chemical that, when in solution, emits hydroxyl ions -{OH). We can also define a base as a substance that releases hydroxyl ions (OH-), which mix with any hydrogen ions (H+) in the solution to generate water molecules (OH- + H+ = H2O).

Therefore, a substance that receives or accepts hydrogen ions (H+) that are already present in the solution qualifies as a base.

Because it totally dissociates into sodium ions (Na+) and hydroxyl ions (OH-) when placed in water, sodium hydroxide (NaOH), which is a strong base, is now liberated and dissolves in water.

c

for more information please visite:

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8 0
2 years ago
What is disproportionation reaction and give one example of it ?​
mario62 [17]

Answer:

A disproportionation reaction is when a multiatomic species whose pertinent element has a specific oxidation state gets oxidized and reduced in two separate half-reactions, yielding two other products containing the same pertinent element. A convenient example is Mn2O3 becoming Mn2+ and MnO2 .

4 0
3 years ago
Read 2 more answers
Using your knowledge of reagents that react with alkenes, what would be a reagent that you could use to check and see if the hyd
igomit [66]

Answer:

An halogen addition reaction, particularly bromine addition, could be used to check if the hydrogenation has completed.

Explanation:

The aim is to find a way to check if the hydrogenation process of an alkene has completed. So the logic should be use a reaction that needs the participation of the double bound of the alkene, and therefore shouldn't take place in the process has finished.

A simple organic reaction is the halogen addition reaction, which occur between the halogen molecule and the double bond of the alkene. Basically, the pi electrons of the double bond attacks a relatively electrophilic halogen atom following a mechanism that leads to the addition of two halogen atoms to the double bond. As a consequence the alkene transforms into an haloalkane.

Also, a commonly used halogen is bromine, as it has a reasonable reactivity and it has red colour, which allows to monitor the progression of the reaction.

Taking all this in account, we can say that using a bromine addition reaction to the alkene it's a good option to check the completion of the hydrogenation.

Note that the bromine will react only if the double bond is present. So, if the hydrogenation has completed, the reaction won't occur. Using bromine will be the best option, as it is red coloured. That means that is we add bromine to an incomplete hydrogenation, as it will react with the alkene, the colour should disappear.

In other words, to check if the hydrogenation reaction has completed, we should add bromine and see what happens to the colour. If it doesn't change, then the hydrogenation reaction has completed.

3 0
3 years ago
A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reacta
melomori [17]
Cao +  H2O  ---->Ca(OH)2
Calculate   the  number  of  each   reactant  and  the  moles  of  the  product
that  is
moles = mass/molar mass
The  moles  of  CaO=  56.08g/  56.08g/mol(molar  mass  of  Cao)=  1mole
the  moles  of  water=  36.04 g/18  g/mol=  2.002moles
The   moles  of Ca (OH)2=74.10g/74.093g/mol= 1mole

 The  mass  of differences  of  reactant  and  product  can   be  therefore 
 explained  as 
 1  mole   of  Cao  reacted  completely   with   1  mole   H2O  to  produce  1 mole  of  Ca(OH)2. The  mass  of  water   was  in  excess  while  that  of  CaO  was  limited

3 0
3 years ago
Sodium hydride reacts with excess water to produce aqueous sodium hydroxide and hydrogen gas:NaH (s) H2O (l) → NaOH (aq) H2 (g)A
Anuta_ua [19.1K]

NaH(s)+ H2O (l)=>NaOH(aq)+H2(g)

You want to calculate the mass of NaH, I assume.  Otherwise, the question isn't clear.  It simply says calculate the mass(??)

 

So, calculate the moles of H2 gas that satisfy the conditions of 982 ml at 28ºC and 765 torr.  But you must subtract the vapor pressure of water at 28º to get the actual pressure of the H2 gas.  So, the actual conditions are 982 ml (0.982 L) and 301 K and 765-28 = 737 torr.

PV = nRT

n = PV/RT = (737 torr)(0.982 L)/(62.4 L-torr/Kmol)(301 K)

n = 0.0385 moles H2

 

moles NaH needed = 0.0385 moles H2 x 1 mole NaH/mole H2 = 0.0385 moles NaH required

mass of NaH needed = 0.0385 moles x 24 g/mole = 0.925 g NaH

Brainliest Please :)

7 0
3 years ago
Read 2 more answers
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