How many grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene

1 answer:

8 0

Complete combustion of acetylene generated carbon dioxide and water. This can be represent by following reaction

2C2H2 + 5O2 → 4CO2 + 2H2O
(2 mole) (4 mole)

From the above balanced reaction, it can be seen that 2 mole of acetylene on complete combustion generates 4 moles of carbon dioxide
i.e. 2 mole of C2H2 ≡ 4 mole of CO2
∴ 1.3 mole of C2H2 ≡ (4 X 1.3)/2 = 2.6 mole of CO2

Now, 1 mole of CO2 = 44 g
∴ 2.6 mole of CO2 = (44 X 2.6) = 114.4 g

Thus, 114.4 grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene

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