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alekssr [168]
3 years ago
10

How many grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0
Complete combustion of acetylene generated carbon dioxide and water. This can be represent by following reaction

2C2H2   +    5O2     →      4CO2     +     2H2O
(2 mole)                            (4 mole)

From the above balanced reaction, it can be seen that 2 mole of acetylene on complete combustion generates 4 moles of carbon dioxide
i.e. 2 mole of C2H2 ≡ 4 mole of CO2
∴ 1.3 mole of C2H2 ≡ (4 X 1.3)/2 = 2.6 mole of CO2

Now, 1 mole of CO2 = 44 g
∴ 2.6 mole of CO2 = (44 X 2.6) = 114.4 g

Thus,  <span>114.4 grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene</span>
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Sixty miles/hour is how many ft/sec
Karo-lina-s [1.5K]
88 foot per second. 
5280 feet = 1 mile

5280 × 60 = 316800

316800 feet per hour

3600 seconds = 1 hour

316800 feet per 3600 seconds

316800 ÷ 3600 = 88

88 feet per second

5 0
3 years ago
6. Which of the following could be a base in a water solution?
Elza [17]

Answer:

h20

Explanation:

H2O is an acid and a base, and H20 is water.

5 0
3 years ago
Sevin, the commercial name for an insecticide used to protect crops such as cotton, vegetables, and fruit, is made from carbamic
xeze [42]

Answer:

Explanation:

Ratio of mass of C , N , H and O

= .8007 :0.9333:0.2016:2.133

Ratio of moles of C , N , H and O

= .8007/12 : .9333 / 14 : 0.2016 / 1 : 2.133/16

= .0667 : .0667: .2016 : .1333

= .0667 / .0667 : .0667 / .0667 : .2016 /.0667 : .1333 / .0667

= 1 : 1 : 3: 2

Hence empirical formula = CNH₃O₂

7 .

Weight of titanium Ti = 1.916 g

Weight of oxygen = 3.196 - 1.916 = 1.28 g

Ratio of weight of Ti and O

= 1.916 : 1.28

Ratio of moles  of Ti and O

1.916/48 : 1.28/16  [ Molecular  weight of Titanium is 48 ]

= .04 : .08

= .04/.04 : .08/.04

= 1 :2 .

Empirical formula

TiO₂

5 0
2 years ago
P-fluoroanisole reacts with sulfur trioxide and sulfuric acid. Draw the major product of this substitution reaction; if applicab
Ipatiy [6.2K]

Answer: (Structure attached).

Explanation:

This type of reaction is an aromatic electrophilic substitution. The overall reaction is the replacement of a proton (H +) with an electrophile (E +) in the aromatic ring.

The aromatic ring in p-fluoroanisole has two sustituents, an <u>halogen</u> and a <u>methoxy group</u>, which are <em>ortho-para</em> directing substituents.

Aryl sulfonic acids are easily synthesized by an electrophilic substitution reaction aromatic using <u>sulfur trioxide as an electrophile</u> (very reactive).

The reaction occurs in three steps:

  1. The attack on the electrophile forms the sigma complex.
  2. The loss of a proton regenerates an aromatic ring.
  3. The sulfonate group can be protonated in the presence of a strong acid (H₂SO₄).

Normally, a mixture of <em>ortho-para</em> substituted products would be obtained. However, since both <em>para</em> positions are occupied, only the <em>ortho </em>substituted product is obtained here.

8 0
3 years ago
Don’t mind my cats fur :)
denpristay [2]

Answer:

Potassium is an element, with the symbol K

Explanation:

An element is something that cannot be broken down any further, for example, calcium, its Ca.

A compound is when you bond two or more elements. Compounds can be broken down into its original elements, for example, H₂O, it contains two atoms of hydrogen and one atom of oxygen (both hydrogen and oxygen are elements).

8 0
3 years ago
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