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3 years ago

Which type of bond will form between these elements? *

Chemistry

1 answer:

BlackZzzverrR [31]3 years ago

6 0

Answer:

Please mention elements so i can answer it

Explanation:

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There is no overall change in reactants and products whenever a chemical reaction a. goes in just one direction. b. goes in two

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There is no overall change in reactants and products whenever a chemical reaction reaches equilibrium. It is a fundamental point in a reaction.

<h3>Chemical reactions</h3>

A chemical reaction is a process where one or more reactants interact with an enzyme to generate one or more products.

The equilibrium refers to the state where reactants and products are found in the same concentrations.

During the equilibrium, there is no change in the properties of the reaction and the amounts of substances involved remain the same.

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2 years ago

Which of the following diatomic gases has the shortest bond between its two atoms?

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3 years ago

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What is the maximum number of electrons in the following energy level? n = 2

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<span>What is the maximum number of electrons in the following energy level? n = 2

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4 years ago

Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$