Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
(11/12) / (2 5/8) = ...turn mixed numbers to improper fractions
(11/12) / (21/8) = ...when dividing fractions, flip what u r dividing by, then multiply
11/12 * 8/21 = 88/252 reduces to 22/63
Add 5ft 7in and 4ft 8in together
5ft 7in + 4ft 8in = 10ft 3in
Answer:
yes
Step-by-step explanation:
nothing much u have to do like what ur teacher said
Answer:
69 :D
Step-by-step explanation:
its a funny number :v
