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2 years ago

What is the area of the square below?

Mathematics

1 answer:

Sedbober [7]2 years ago

5 0

Answer:

O C. 5.76 in2

Step-by-step explanation:

To find the <u>area</u> of a square, the formula is

length x width = area

length = 2.4

width = 2.4

2.4in x 2.4in = 5.76 in2

in2 is the part of the answer since in x in = in2

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Write an equation in point-slope form of the line that passes through the given point and has the given slope. (3, –8); m = –5

Paraphin [41]

Answer:

y+8=-5(x-3)

Step-by-step explanation:

The formula for point-slope form is y-y1=m(x-x1)

The points for (x1, y1) are (3, -8), meaning that 3 is x1 and -8 is y1.

So, start by writing your equation like this: y--8=m(x-3)

For the equation y--8=m(x-3), the y--8 will change to a + sign because two negatives make a positive, right? So, the equation should now look like this: y+8=m(x-3).

We know that the slope (m) is -5. Plug that into the equation to get this: y+8=-5(x-3)

And there you have it!! The equation is now in point-slope form!!

y+8=-5(x-3) is the final answer!!

Hope that helps you!! Please give me brainliest!!

7 0

3 years ago

What are the factors of 68

elixir [45]

$68=2\times34\\\\68=4\times17$

4 0

3 years ago

Read 2 more answers

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

7 0

3 years ago

Read 2 more answers

Could you help me quick!?

anastassius [24]

Answer:

1: 5 2: -70.98 3: C 4:A. 5:A

Step-by-step explanation:

4 0

3 years ago

Pls help :)) this question is confusing for me :)

Temka [501]

Given:

$y^{2}(2 y-5)-8 y+20$

To find:

The product of the expression.

Solution:

$y^{2}(2 y-5)-8 y+20=y^{2}(2 y-5)+(-8 y+20)$

Take out -4 as a common factor in Last two terms.

$=y^{2}(2 y-5)-4(2 y-5)$

Make sure the terms in both brackets must be same.

Take out common factor (2y - 5) from both terms.

$=(2 y-5)(y^{2}-4)$

4 can be written as 2².

$=(2 y-5)\left(y^{2}-2^2\right)$

Using the identity: $(a^2-b^2)=(a-b)(a+b)$

$=(2 y-5)(y-2)(y+2)$ .

The product is $(2 y-5)(y-2)(y+2)$ .

5 0

3 years ago