Answer:
Measure of ∠K=180-∠U
Or
Measure of ∠K=1/2m(arc DUC)
Step-by-step explanation:
Given:
DUCK quadrilateral inscribed in circle with center O
To Find:
Measure angle K
Solution:
Here the Quadrilateral in inscribed in a circle with center O named as DUCK
So angle K and U are opposite to each other
We know that the angle of Quadrilateral inscribed in a circle are supplemenatry angles
Hence
∠U+∠K=180
Or The ∠K=1/2*m∠arc(DUC).
Hence depending on the given value for arc measure or angle of quadrilateral we calculate the angle K
Answer:
p(x) = A(x - 4i)(x + 4i)(x - 3)(x + 3), with A = 1.
it matches
Answer: x>-6
Explanation: -2x -6>-18
-2x >-12
-x>6
X>-6
Answer:
584.57
Step-by-step explanation:
Okay so, togo flies 30 miles in 3/5 of an hour with the wind.togo flies 30 miles in 5/6 of an hour against the wind. his rate of speed with the wind was 30 / (3/5) = 30*5/3 = 150/3 = 50 mph.his rate of speed against the wind was 30 / (5/6) = 30*6/5 = 6*6 = 36 mph.3/5 of an hour times 50 mph = 30 miles.
5/6 of an hour times 36 mph = 30 miles.mph looks good.
going he was with the wind.
his rate of speed then was the airplane speed plus the wind speed.coming back he was against the wind.his rate of speed then was the airplane speed minus the wind speed.-----50 mph = A + W36 mph = A - W-----looks like A + W - (A - W) should equal 50 - 36.removing parentheses, equation becomesA + W - A + W = 14.
combining like terms, the equation becomes2*W = 14.dividing both sides by 2, equation becomesW = 7.if W = 7, then A can be found as follows:50 = A + 7A = 43.likewise,36 = A - 7A = 43.since the airplane speed is the same, it looks like the answer is good.solving in the original equations, we get3/5 * (43 + 7) = 303/5 * 50- = 3030 = 30good.-----5/6 * (43 - 7) = 305/6 * 36 = 3030 = 30good.
answer is W = 7 and A = 43.
