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lidiya [134]
3 years ago
10

Are the equations 3x - -9 and 4x - -12 equivalent? Explain. Please Help!!

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0
No because  when  you do 3*--9 = 27 and 4*--12 =48

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Identify the common difference. -6, -3, 0, 3, 6....
Nikolay [14]

Answer:

3

Step-by-step explanation:

5 0
3 years ago
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At a certain time of day, a tree that is x meters tall casts a shadow that is x−46x−46 meters long. if the distance from the top
Alexus [3.1K]
By the Pythagorean theorem,
.. x^2 +(x -46)^2 = (x +4)^2
.. 2x^2 -92x +2116 = x^2 +8x +16
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.. (x -50)^2 -400 = 0
.. x = 50 ±20 . . . . . only x=70 makes any sense in the problem

The height, x, of the tree is 70 meters.
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3 years ago
The ratio of the perimeters of two similar triangles is 4:3. What are the areas of these triangles if the sum of their areas is
emmasim [6.3K]

Answer:

the areas of these triangles are 83.2cm² and 46.8cm²

Step-by-step explanation:

1. If the triangles are similar and the ratio of the perimeter ois 4:3, then the areas are in the following ratio:

4²:3²

 16:9                                                                      

2. The sum of their areas is 65 cm², then, you can calculate the area of the larger triangle as following:

130(16/16+9)

130(0.64)

=83.2cm²

3. The area of the smaller triangle is:

130(9/16+9)

130(0.36)

46.8cm²

<u>Hope this help</u>s

6 0
2 years ago
Geometry please help!
ikadub [295]

Answer:

see explanation

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

The polygon here has 8 sides, that is n = 8, thus

sum = 180° × 6 = 1080°

Sum the given angles and equate to 1080, that is

14x + 133 + 167 + 138 + 18x + 115 + 151 + 120 = 1080

32x + 824 = 1080 ( subtract 824 from both sides )

32x = 256 ( divide both sides by 32 )

x = 8

Thus the 2 unknown angles are

14x = 14 × 8 = 112°

18x = 18 × 8 = 144°

8 0
3 years ago
BRAINLIEST ASAP! PLEASE HELP :) A
VashaNatasha [74]
I think it’s, Gross profit margin.
5 0
3 years ago
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