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Nat2105 [25]
3 years ago
13

List the next four multiples of the unit fraction 1/5,

Mathematics
1 answer:
svetoff [14.1K]3 years ago
6 0
Next multiples of the unit fraction 1/5 are
2/5
3/5
4/5
5/5 = 1

Hope this helps..  :)
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Find an equation of cosine function with maximum of 7, minimum of -7 and period of 7
Galina-37 [17]

Answer:   \bold{y=7cos\bigg(\dfrac{2\pi}{7}x\bigg)}

<u>Step-by-step explanation:</u>

y = A cos (Bx - C) + D

  • A = amplitude (vertical stretch)
  • Period = 2π/B
  • C/B = phase shift
  • D = vertical shift

The minimum is -7 and the max is 7 so A = 7 and D = 0

Period is 7.  Since P = 2π/B then 7 = 2π/B --> B = 2π/7

Nothing was stated about a phase shift so you can use any value for C. I chose C = 0.

Now, input A = 7, B = 2π/7, C = 0, & D = 0 into the equation

y=7\cos\bigg(\dfrac{2\pi}{7}x-0\bigg)+0\\\\\\\text{Simplify}:\\y=7\cos\bigg(\dfrac{2\pi}{7}x\bigg)

3 0
3 years ago
Given that f(x)= <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-3%20%7D%7B2%7D" id="TexFormula1" title="\frac{x^{2}-3 }
torisob [31]

Answer:

x=5,-5

Step-by-step explanation:

\\ y=\frac{x^2-3}{2}\\\\ x=\frac{y^2-3}{2}\\\\ 2x=y^2-3\\\\ y^2=2x+3\\\\ f^{-1}(x)=\pm\sqrt{2x+3}\\\\ f^{-1}(x)=\pm\sqrt{2(11)+3}\\=\pm\sqrt{25}=\pm 5

5 0
3 years ago
-2&lt;× and x&lt;7<br><img src="https://tex.z-dn.net/?f=%20-%202%20%3C%20x" id="TexFormula1" title=" - 2 &lt; x" alt=" - 2 &lt;
bixtya [17]

Answer:

-2 < x < 7

Step-by-step explanation:

And implies intersection

x can be anything greater than -2 but it also has to be less than 7.

Therefore between -2 and 7

7 0
3 years ago
What is the slope of this graph please no links or files
Ad libitum [116K]
The answer is 2/3 , you go up 2 and to the right 3 which means it is a positive slope of 2/3.
7 0
3 years ago
Read 2 more answers
Use any method to work these out, but do NOT use a calculator.
Artemon [7]

Answer:

A) 216

B) 64.5

Step-by-step explanation:

         40

x     5.40

___________

You can solve it like that, I don't remember what it is called.

4 0
3 years ago
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