The zeroes of this function are x = 2, 4.
We can find this by factoring. Factoring x²-6x+8, we get (x-2)(x-4). Now, since we want to find the zeroes, we have to make y equal to zero, or (x-2)(x-4) = 0. Using the zero-product property, we can conclude that if (x-2)(x-4) is 0, x is 2, 4.
8x + 5 = 3x + 15
8x - 3x = 15 - 5 (put same kinds of number on one side and change the signs)
5x = 10 (simplify)
5x/5 = 10/5 (simplify)
x = 2 (answer)
hope this helps
There are six sides on each die. For each possible score on Die 1, there are six possible scores on Die 2. So the number of possible combinations is 6*6 = 36.
<span>It follows that if the dice are thrown 36 times, you would expect each combination to come up once. </span>
<span>We therefore simply need to know how many combinations add up to less than 5. (I've interpreted this as not including a total of 5 itself). </span>
<span>These combinations are: 1 and 1, 2 and 1, 1 and 2, 2 and 2, 3 and 1, and 1 and 3 ---> six combinations out of 36. </span>
<span>So you'd expect a sum less than 5 six times. </span>
