When a function is shifted to the right by 1 unit it is moved towards the negative side so we would be adding -1 to the value of x. The function f(x) would be f(x-1). To determine the resulting function, we substitute to the parent function (x-1) to x. We do as follows:
<span>f (x) = x^3 + 2x^2 − 3x − 5
</span>f (x-1) = (x-1)^3 + 2(x-1)^2 − 3(x-1) − 5
f (x-1) = x^3 - 3x^2 + 3x - 1 + 2(x^2 - 2x + 1) - 3x + 3 - 5
f (x-1) = x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5
f (x-1) = <span>x^3 - x^2 - 4x - 1
Therefore, the correct answer is the last option.</span>
If two angles are complimentary then their sum would equal to 90 degree.
i.e., x + 3x + 30 = 90
4x = 90 - 30
x = 60 / 4
x = 15
In short, Your Answer would be Option A
Hope this helps!
Using the asymptote concept, it is found that:
- The vertical asymptote is of x = 25.
- The horizontal asymptote is of y = 5.
- Considering the horizontal asymptote, it is found that the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, the function is:

Considering the denominator, the vertical asymptote is:
x - 25 = 0 -> x = 25.
The horizontal asymptote is found as follows:

Hence the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.
More can be learned about asymptotes and end behavior at brainly.com/question/28037814
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0.31 rounded to the nearest tenth would be 0.3
This Chart should help you in the future: