7.2 km away from her starting point
hope I helped you:)
Answer:
46
add all the number together and divide by how many there is
Answer:
the hawk has flow 824.62 meters southwest of the mountain peak.
Step-by-step explanation:
In order to find the distance we need to use the Pythagoras theorem
d^2 = 800^2 + 200^2
d= 824.6 m
we can find the direction by using the eq for a tangent
he opposite side is 200 m and the adjacent side is 800m
tan theta = opposite / adjacent
theta = arc tan (800/200)
The hawk is at a distance of 824.6m flying at an angle 76 degrees NE of the mountain peak.
The final location will be southwest of the mountain peek.
a2+b2=c2
a = 200
b= 800
c = √(2002+8002) = 824.62
So the hawk has flow 824.62 meters southwest of the mountain peak.
2/15 = x/75
15x = 2(75)
<u>15x = 150
</u> 15
x = 10
10/75
Let me fill in the statement reasoning for you:
Statement | Reasoning
∆ABC ~ ∆RST Given
∆DEF ~ ∆RST
∠A = ∠R, ∠D = ∠R Definition of ~ ∆
∠C = ∠T, ∠F = ∠T
∠A = ∠D,∠C = ∠F Transitivity
∆ABC ~ ∆DEF AA