Answer: Fifth grade mean: 4.67
Seventh grade mean: 3.46
Fifth grade median: 5
Seventh grade median: 3.5
Step-by-step explanation: I just did the question
Answer:
- (4x -4)° +x° +(6x-3)° = 180°
- J = 99°
- K = 64°
- L = 17°
Step-by-step explanation:
The relation that helps you write an equation for x is, "the sum of angles in a triangle is 180°."
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<h3>equation</h3>
(4x -4)° +x° +(6x -3)° = 180° . . . . . sum of angles in this triangle
<h3>solution for x</h3>
11x -7 = 180 . . . . . . . divide by °, collect terms
11x = 187 . . . . . . . . add 7
x = 17 . . . . . . . . . divide by 11
<h3>angle values</h3>
m∠J = (6x -3)° = (6(17) -3)° = 99°
m∠K = (4x -4)° = (4(17) -4)° = 64°
m∠L = x° = 17°
Let's break it down:
We need an LCM, a least common multiple, so it's easier to subtract
3 1/4x + 7 1/14
-
1/8x - 2 5/7
3 1/4 is equivalent to 3 2/8
2 5/7 is equivalent to 2 10/14
3 2/8x + 7 1/14 or you can break it down to two parts also
- 3 2/8x - 1/8x = 2 1/8x
1/8x - 2 10/14 7 1/14 - (-2 10/14) = 9 11/14
------------------ - - = +
2 1/8x + 9 11/14
Answer:
Second option: On a coordinate plane, rectangle A'B'C'D' prime has points
(See the graph attached)
Step-by-step explanation:
For this exercise it is importnat to know that a Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) has the same shape as the Pre-Image (which is the original figure before the transformation), but they have different sizes.
In this case, you know that the vertices of the rectangle ABCD ( The Pre-Image) are the following:

Therefore, to find the vertices of the rectangle A'B'C'D' (The Image) that results of dilating the rectangle ABCD by a factor of 4 about the origin, you need to multiply the coordinates of each original vertex by 4. Then, you get:

Finally, knowing those points, you can identify that the graph that shows the result of that Dilation, is the one attached.