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3 years ago

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the area of one circle is 9 times as great as the area of another. If the radius of smaller circle is 3, find the radius of larg

er circle.

1 answer:

Lunna [17]3 years ago

4 0

Make the larger circle A and the smaller circle B or any other letters so you can find it less confusing. hope this helps

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The temperature is currently 60 F. If the temperature drops on average 2 degrees per day, how many days will it be until the tem

Bezzdna [24]

9 days

because legit 60 - 42 = 18
18 divide 2 = 9 days

Or you could’ve just done 42 + 2 +2+2 until you get to 60 and you would do it 9 times. Meaning 9 days

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2 years ago

Match with correct description

fgiga [73]

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3 years ago

In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º. Find the area of ABCD

dmitriy555 [2]

Answer:

The area of parallelogram ABCD is $78.42 \mathrm{in}^{2}$

Explanation:

Given:

AD = 12 in

$m \angle C=46^{\circ}$

$m \angle D B A=72^{\circ}$

To Find:

The area of parallelogram ABCD=?

Solution:

When we construct the parallelogram with the given data, we get a parallelogram formed by 12 cm as one side and an angle with 46 degrees.

The area of the parallelogram can be calculated by $a b * \sin (a n g l e)$

Substituting the value of a=12 we have

$\text { Area of parallelogram }=12 * \text { bsin } 46$

<u>To find the value of b, </u>

We know that area of a triangle can be expressed as,

$\text { Area of triangle }=(A b / 2) \sin (\text {angle})$

So,

$(12 * B D / 2) * \sin 46=(A B * B D / 2) * \sin 72$

Cancelling BD and 2 on both sides we get,

$12 * \sin 46=A B * \sin 72$

$A B=12 * \frac{\sin 46}{\sin 72}$

Therefore,

$b=\frac{12 \sin 46}{\sin 72}$

Substituting the value of b,

$=12 *\left(\frac{12 \sin 46}{\sin 72}\right) * \sin 46$

=78.42

So the area of the parallelogram is $78.42 \mathrm{in}^{2}$

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Answer:

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