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3 years ago

Please help me with math

Mathematics

1 answer:

dezoksy [38]3 years ago

4 0

Answer:

Step-by-step explanation:

The answer is:

s= -1 and t = - 1

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Which statement is true?

SVEN [57.7K]

Answer:

$y=log_{1} x$ is not a logarithmic function because the base is equal to 1.

Step-by-step explanation:

A logarithmic function is of the form: $y=log_{b}x$

For a logarithmic function to exist, we must fulfill certain conditions. The conditions are

i. The base, $b$ , is greater than 0. ${b>0)$

ii. The base, $b$ , is not equal to 1. $(b\ne 1)$

iii. $x$ must be greater than 0. $(x>0)$

Now, if we observe all the choices given, we conclude that the third choice is correct as the base there is 1. If base is equal to 1, then it violates the definition of logarithmic functions. So, the correct choice is:

$y=log_{1} x$ is not a logarithmic function because the base is equal to 1.

6 0

3 years ago

Read 2 more answers

Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From

maksim [4K]

Answer:

The 95% CI for the difference of means is:

$-155.45 \leq \mu_1-\mu_2 \leq -44.55$

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size: 4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

$M_d=M_1-M_2=200-300=-100$

The standard deviation can be estimated as:

$\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45$

The degrees of freedom are:

$df=n_1+n_2-2=10+4-2=12$

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

$M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55$