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saveliy_v [14]
3 years ago
14

NEED HELP ASAP PLEASE

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

Answer:

  7. Distributive Property

  8. 8x +2.5

Step-by-step explanation:

7. The equation matches the pattern ...

  a(b + c) = ab + ac  . . . . . . .  statement of Distributive Property

with a=√2, b=5, c=4

__

8. The one-time charge of 2.50 will appear added in the equation one time (and not multiplied by anything). The number of tickets (x) will be multiplied by the ticket charge (8) and added to the one-time charge. Only one answer choice does that:

  8x + 2.5

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Tyson can type 49 words per minute. How long will it take him to type a 1000-word essay?
earnstyle [38]

Answer:

<u>20.4minutes</u>

Step-by-step explanation:

<em>Duration= Number of words/Typing speed</em>

<em>Duration</em><em>=</em><em> </em><em>100</em><em>0</em><em>/</em><em> </em><em>49</em><em> </em><em>per</em><em> </em><em>min</em>

<em>=</em><em> </em><em>20.4minutes</em><em> </em>

Hope this helped you- have a good day bro cya)

8 0
2 years ago
Which type of function is shown in the table below?
sveticcg [70]

Answer:

 Exponential

Mark brainliest :)

7 0
2 years ago
A student comes to lecture at a time that is uniformly distributed between 5:09 and 5:14. Independently of the student, the prof
scZoUnD [109]

Answer:

1/2

Step-by-step explanation:

The lecture has already begun when the student arrives means one of these scenarios happen:  

1) the class started at 5:10 and the student arrives at 5:11 or 5:12 or 5:13 or 5:14

2) the class started at 5:11 and the student arrives at 5:12 or 5:13 or 5:14

3) the class started at 5:12 and the student arrives at 5:13 or 5:14

Given student time of arrival is uniformly distributed, then the probability he/she arrives at 5:09 or 5:10 or 5:11 or 5:12 or 5:13 or 5:14 is 1/6.

So,  the probability that the student arrives between 5:11 and 5:14 is 1/6 + 1/6 + 1/6 + 1/6 = 2/3.

The probability that the student arrives between 5:12 and 5:14 is 1/6 + 1/6 + 1/6 = 1/2.

The probability that the student arrives at 5:13 or 5:14  is 1/6 + 1/6 = 1/3.

Given class starting time is uniformly distributed, then the probability it starts at 5:10 or  5:11 or 5:12 is 1/3.

Given the two events are independent, the probability of the first scenario is: (1/3)*(2/3) = 2/9

For the second scenario:  (1/3)*(1/2) = 1/6

For the third scenario:  (1/3)*(1/3) = 1/9

Because all of these scenarios are mutually exclusive the total probability of one of them happen is: 2/9 + 1/6 + 1/9 = 1/2

3 0
2 years ago
In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5
Nat2105 [25]

Answer:

0.79, - 2.12

Step-by-step explanation:

7 0
3 years ago
A rental car company charges $60.00 just to rent a car, and $70.00 for each day you keep the car.
slava [35]

Answer:

$200

Step-by-step explanation:

70 x 2 = 140.00 + 60.00 = $200

8 0
2 years ago
Read 2 more answers
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