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3 years ago

HELP I THINK ITS EITHER C OR D BUT IDK

Mathematics

2 answers:

IrinaK [193]3 years ago

7 0

Answer:

It's just c

Step-by-step explanation:

That's what corresponding angles look like? I don't really know how to explain this. Sorry!

marusya05 [52]3 years ago

4 0

Answer:

Hey please can you help me with Lesson 8 Unit 4? im confused on it! But it D!

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What is the missing reason in steps 7 and 8 of the proof?

il63 [147K]

Answer:Refer to the image attached.

Given: and are congruent.

To Prove: ABC is an isosceles triangle.

Construction: Construct a perpendicular bisector from point B to Line segment AC.

Consider triangle BAD and BCD,

(given)

(By the definition of a perpendicular bisector)

Therefore, by Angle Side Angle(ASA) Postulate.

Line segment AB is congruent to Line segment BC because corresponding parts of congruent triangles are congruent.(CPCTC)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find all the missing elements. NEED HELP PLZZZZ

IgorC [24]

Answer:

B=42°

C=98°

c=10.7 units

Step-by-step explanation:

Given

Angle A = Ф = 40°
a=8
b=7

We know that trigonometric ratio as

sin Ф = opposite/hypotenuse

cos Ф = adjacent/hypotenuse

tan Ф = opposite/adjacent

sin A = sin 40 = opposite/hypotenuse

From the diagram, it is clear that the opposite of angle A is a=8 and the hypotenuse is 'c'.

also the angle

sin A = sin 40 = opposite/hypotenuse = a/c = 8/c

sin 40 = 8/c

c = 8/sin 40

c = 8/0.745

c = 10.7

so the value of c will be: 10.7 units

tan B = opposite/adjacent

= b/a

= 0.9

$B=\tan ^{-1}\left(0.9\right)$

$=42^{\circ \:}$

Therefore, the value of B = $42^{\circ \:}$

As the sum of the angles of triangle ABC is 180.

i.e.

A+B+C = 180

(40)° + (42)° + C = 180°

C = 180° - 40° - 42°

= 98°

Therefore, the value of C = 98°

Hence,

B=42°

C=98°

c=10.7 units

7 0

3 years ago

A circle has a diameter of 20 mm what is it’s circumference? Use 3.14 for pi and do not round your answer

Dvinal [7]

Answer:

94.2

Step-by-step explanation:

circumference is d(pi)

20(3.14) = 94.2

8 0

3 years ago

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Consider the following differential equation to be solved by undetermined coefficients. y(4) − 2y''' + y'' = ex + 1 Write the gi

kompoz [17]

Answer:

The general solution is

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2}$

Step-by-step explanation:

Step :1:-

Given differential equation y(4) − 2y''' + y'' = e^x + 1

The differential operator form of the given differential equation

$(D^4 -2D^3+D^2)y = e^x+1$

comparing f(D)y = e^ x+1

The auxiliary equation (A.E) f(m) = 0

$m^4 -2m^3+m^2 = 0$

$m^2(m^2 -2m+1) = 0$

$(m^2 -2m+1) this is the expansion of (a-b)^2$

$m^2 =0 and (m-1)^2 =0$

The roots are m=0,0 and m =1,1

complementary function is $y_{c} = (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x$

<u>Step 2</u>:-

The particular equation is $\frac{1}{f(D)} Q$

P.I = $\frac{1}{D^2(D-1)^2} e^x+1$

P.I = $\frac{1}{D^2(D-1)^2} e^x+\frac{1}{D^2(D-1)^2}e^{0x}$

P.I = $I_{1} +I_{2}$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x + \frac{1}{D^{2} } e^{0x}$

$\frac{1}{D} means integration$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x = \frac{1}{2D} \int\limits {x^2e^x} \, dx$

applying in integration u v formula

$\int\limits {uv} \, dx = u\int\limits {v} \, dx - \int\limits ({u^{l}\int\limits{v} \, dx } )\, dx$

$I_{1}$ = $\frac{1}{D^2(D-1)^2} e^x$

$\frac{1}{2D} (e^x(x^2)-e^x(2x)+e^x(2))$

$\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

$I_{2}$ $= \frac{1}{D^2(D-1)^2}e^{0x}$

$\frac{1}{D} \int\limits {1} \, dx= \frac{1}{D} x$

again integration $\frac{1}{D} x = \frac{x^2}{2!}$

The general solution is $y = y_{C} +y_{P}$

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2!}$

3 0

3 years ago

The apparent brightness of a star if it were viewed from a distance of 10 parsecs (32.6 light- years) is called ________.

Maru [420]

Answer:

Absolute magnitude

Step-by-step explanation: Astronomy deals with the study of stars and other heavenly bodies. Astronomers use apparent magnitude to define how bright a star appears and shines from the earth.

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3 years ago