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Romashka-Z-Leto [24]
2 years ago
6

How can a student find how much sand a sandbox can hold if it is 50 inches wide, 67 inches long, and can be filled up to 9 inche

s deep?
A.
use [2(50) × 2(67) × 2(9)] in3
B.
use (50 × 67 × 9) in3
C.
use (50 + 67 + 9) in3
D.
use [2(50) + 2(67) + 2(9)] in3
Mathematics
1 answer:
Sergeu [11.5K]2 years ago
5 0

Answer:

B

Step-by-step explanation:

You would use the formula Length×Width×Height

In this question the length would be 67 in

The height would be 9 in

And the width would be 50 in

The unit of measure is inches

Cubed because this is a 3-dimesional shape

So the answer would be <u>(50×67×9) in³</u>

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2 years ago
Which statement shows the associative property of addition?
AleksAgata [21]
The associative property of addition is shown in equations where the order in which the evaluation is made does not change the result, providing the numbers remain in the same order.  Option B demonstrates this.

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Please help me solve this step by step please :(
Ratling [72]

Answer:

B) 60.21 ft²

Step-by-step explanation:

Area of a triangle = 1/2bh

You can‘t used mixed measurements (feet and inches), so you have to convert each length to inches

8’6”=102’

14’2”=170’

Now find the area

1/2 x 102 x 170 = 8670 in²

This is one of the answers, but the quetion asks how many quart feet you need.

So, convert it back to feet.

8670 x 0.06944444444 = 60.2083333

(You could also have converted the two lengths to feet. 8’6” = 8.5 ft.  14’2” = 14.16666666.  This way would probably have been faster.

1/2 x 8.5 x 14.166666 = 60.20833333)

3 0
3 years ago
The number y of hits a new website receives each month can be modeled by y = 4070ekt, where t represents the number of months th
makvit [3.9K]

Answer:

<u><em>k = 0.2645</em></u>

Step-by-step explanation:

Given model:

y = 4070 e^{kt}

y = no. of hits website received = 9000 (in 3rd month)

t= no. of months website has been operational = 3

put in the above equation:

9000 = 4070  e^{3k}

\frac{9000}{4070} = e^{3k}

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<u><em>Taking natural logarithm on both sides, we get:</em></u>

ln\frac{900}{407}=ln(e^{3k})

ln\frac{900}{407}= 3k ln<em>e</em>

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ln \frac{900}{407}= 3k

or k = \frac{1}{3}ln\frac{900}{(407)}

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<em>k = 0.2645</em>

<em />

7 0
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