Answer:
$2,700
Step-by-step explanation:
Let the width of the pasture be x, this means that the length of the pasture will be 2x
The area of a rectangle is L * B
Hence,
x * 2x = 18,000
2x^2 = 180,000
x^2 = 90000
x = 300 meters
This means the length is 600 metres
Now, to get the length of the fence, we need to know the actual perimeter which is 2(L + B)
= 2 ( 300 + 600)
2 * 900 = 1,800 metres
The cost is thus 1,800 * $1.50 = $2,700
Answer:
14 cm^2
Step-by-step explanation:
You find the area of both triangles, and subtract by 4
6x3x1/2x2 - 2x2
18 - 4
14
If a something with the value of $179,000 dollars decreased in value annually by 3% you would show this by setting a graph or depiction of the drop. You could do this with a line graph to show the slow decrease in value or a bar graph to show how the value is getting smaller
Answer:
A, C
Step-by-step explanation:
Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.
Examining
A) True
![\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}](https://tex.z-dn.net/?f=%5Cfrac%7B1-tan%5E%7B2%7Dx%7D%7B2tanx%7D%20%3D%5Cfrac%7B1%7D%7Btan2x%7D%20%5C%5C%20%5Cfrac%7B1-tan%5E%7B2%7Dx%7D%7B2tanx%7D%20%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B2tanx%7D%7B1-tan%5E%7B2%7Dx%7D%7D%5C%5C%20tan2x%3D%5Cfrac%7B1-tan%5E%7B2%7Dx%7D%7B2tanx%7D)
Double angle ![tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}](https://tex.z-dn.net/?f=tan2%5Calpha%20%3D%5Cfrac%7B1%20-tan%5E%7B2%7D%5Calpha%20%7D%7B2tan%5Calpha%7D)
B) False,
No further development towards a Trig Identity
C) True
Double Angle Sine Formula ![sin2\alpha =2sin\alpha *cos\alpha](https://tex.z-dn.net/?f=sin2%5Calpha%20%3D2sin%5Calpha%20%2Acos%5Calpha)
![sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)](https://tex.z-dn.net/?f=sin%288x%29%3D2sin%284x%29cos%284x%29%5C%5C2sin%284x%29cos%284x%29%3D2sin%284x%29cos%284x%29)
D) False No further development towards a Trig Identity
![[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)](https://tex.z-dn.net/?f=%5Bsin%28x%29-cos%28x%29%5D%5E%7B2%7D%20%3D1%2Bsin%282x%29%5C%5C%20sin%5E%7B2%7D%20%28x%29-2sin%28x%29cos%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B2sinxcosx%5C%5C%20%5C%5Csin%5E%7B2%7D%20%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B4sin%28x%29cos%28x%29)