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gogolik [260]
2 years ago
9

5. Find the volume of the composite space figure to the nearest whole number. (1 point)

Mathematics
1 answer:
-BARSIC- [3]2 years ago
8 0

Answer:

  (d)  944 mm³

Step-by-step explanation:

The volume of a prism is given by the formula ...

  V = Bh

where B is the area of the base, and h is the distance between bases.

__

<h3>base area</h3>

Here, the base of the prism is a rectangle with a semicircle on top. The circle has a diameter of 9 mm, so a radius of 4.5 mm. The area of the semicircle is ...

  A = 1/2πr² = 1/2π(4.5 mm)² ≈ 31.809 mm²

The area of the rectangle is the product of its length and width.

  A = LW = (9 mm)(6 mm) = 54 mm²

So, the total base area is ...

  31.809 mm² +54 mm² = 85.809 mm²

<h3>prism volume</h3>

The prism volume is this area multiplied by the length of the figure:

  V = Bh = (85.809 mm²)(11 mm) ≈ 944 mm³

The volume of the figure is about 944 mm³.

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Answer:

True.

Step-by-step explanation:

Given,

4cos2 (4x) - 3 = 0

Now, 4π/24 = π/6

Or, cos π/6 = √3/2

Or, cos^2 π/6 = 3/4

Or, 4 cos^2 π/6 = 3

Now, Left Hand Side= 4cos2 (4x) - 3

                                  = 3-3 =0 = Right Hand Side (Proved)

Here, Left Hand Side= Right Hanad Side. So, 4cos2 (4x) - 3=0 is true.

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3 years ago
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What is the reciprocal of 4 5/8
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Answer:

8/45

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Write 4 5/8 as an improper fraction:  45/8.

Then invert this result, obtaining:

 .  This is the "reciprocal" of 4 5/8.

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Which expression is equivalent to 2(-3x+5)?<br> A.-6x+5<br> B.-6x+10<br> C.6x-10<br> D.6x-5
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B if you’re doing distributive property
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Select two ratios that are equivalent to 7: 10
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Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am
zheka24 [161]

SOLUTION

We have been given the equation of the decay as

\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}

So we are looking for the time

Plugging the values into the equation, we have

\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}

Taking Ln of both sides, we have

\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}

Hence the answer is 4308 to the nearest year

8 0
1 year ago
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