First solve for the trig function 'cot'
Next take the sqrt of both sides (include plus/minus)
Now take reciprocal of both sides, this will change trig function to 'tan'
(cot = 1/tan)
Finally use the unit circle or inverse tan on your calculator to find x.
There will be 4 solutions, one for each quadrant.
Answer:
(2, -10)
Step-by-step explanation:
so first i find the axis of symmetry using the equation x= -b/2a
in this problem
a=3
b= -12
c= 2
- (-12)/ 2(3) = 2
2 will be the x point for your vertex
you then plug in your x point into the original equation and solve for y
y = 3(2)^2 - 12(2) +2
y = -10
Vertex is then (2, -10)
2 and 5...................... hope I helped
The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
the tangent line is the first derivative of the function</span></span></span><span>y′ = <span>b^2x/ a^2 y
hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1
</span></span></span></span>Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)
Answer:
NO.
Step-by-step explanation:
If it is a right triangle then by the Inverse of the Pythagoras Theorem:
40^2 = 35^2 + 15^2
Testing:
40^2 = 1600
35^2 + 15^2 = 1225 + 225 = 1450
So the answer is NO>
