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deff fn [24]
2 years ago
11

Equation of a circle given a diameter 1-Diameter (2,4) (-3,5) 2-Diameter (2,4) (6,2)

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
8 0

Answer:

harvard

Step-by-step explanation:

they are really nice and smart circles

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The lifetime of two light bulbs are modeled as independent and exponential random variables X and Y, with parameters lambda and
Scorpion4ik [409]

Answer:

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

Step-by-step explanation:

The PDF of X is

\bf f(x)=\lambda e^{-\lambda x}\;(x\geq0)

The PDF of Y is

\bf g(x)=\mu e^{-\mu x}\;(x\geq0)

The means of X and Y are respectively,

\bf \displaystyle\frac{1}{\lambda}\;,\displaystyle\frac{1}{\mu}

so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.

Therefore, the PDF of Z is

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

7 0
3 years ago
After releasing of radioactive material into.The atnosphere from.A nuclear.Powe plant in a country in 1988, the hay in that coun
Radda [10]

Answer:

the question is incomplete, so I looked for a similar one:

<em>After the release of radioactive material into the atmosphere  from a nuclear power plant, the hay was contaminated by iodine  131 ( half-life, 8 days). If it is all right to feed the hay to cows  when 10% of the iodine 131 remains, how long did the farmers  need to wait to use this hay? </em>

iodine's half life (we are given x, we need to find b):

0.5A₀ = A₀eᵇˣ

x = 8 days

we eliminate A₀ from both sides

0.5 = eᵇ⁸

ln 0.5 = ln eᵇ⁸

-0.69315 = b8

b = -0.69315 / 8 = -0.08664

since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):

0.1A₀ = A₀eᵇˣ

0.1 = eᵇˣ

ln 0.1 = bx

where b = -0.08664

x = ln 0.1 / -0.08664  = -2.302585 / -0.08664  = 26.58 days

4 0
3 years ago
Someone help me with this please!
kifflom [539]

Answer:

input:                    x+4                   output        (x,y)

-2                        -2 + 4 =2               2             (-2,2)

0                          0 + 4 = 4              4              (0,4)

2                           2 + 4 = 6              6             (2,6)

...

Step-by-step explanation:

continue by plugging in x to the equation, x is input and y is output

then just plot your (x,y) points on the graph.

4 0
3 years ago
What is the equation of the line that passes through the point (9, 6) and is perpendicular to the line y = 3x - 5?
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

y = 3x - 5

m₁ = 3

The required line is perpendicular to y = 3x - 5. Let the required line's slope be m₂

m₂ = -1/m₁

m₂ = -1/3

Point (9,6)

Equation of line: y - y₁ = m(x - x₁)

y - 6 = (-1/3)(x - 9)

y-6=\frac{-1}{3})x+\frac{1}{3}*9\\\\y-6=\frac{-1}{3}x+3\\\\y=\frac{-1}{3}x+3+6\\\\y=\frac{-1}{3}x+9\\

5 0
3 years ago
How many 1 2/3 yard lengths of wire can be cut from 25 yards of wire?
timofeeve [1]
Divide 25 by 1 2/3 or 1.66 and then round down to get 15

8 0
3 years ago
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