( 7 x 4 ) ^4 = 7^4 x 3^4
The rule is:
( a * b )^n = a^n * b^n
Answer:
D ) Power of a Product Property
9514 1404 393
Answer:
G
Step-by-step explanation:
The one point with a y-value of 0 is the one on the x-axis: G.
Answer:
y=mx+b is slope-intercept form
where m is the slope and b is the y intercept.
Since the line crosses the y axis at 0,0 the intercept is +0 or just nothing.
now all we need to do is find the slope
to do that just go from the y intercept (the first point) y units up and x units over untill u cross at the next point. for examples from (0, 0) to (1, 8)-the next point- i need to go up 8 units up and 1 unit over. this is described as rise over run and that is your slope 8/1 rise/run. rise is how many units i go up (or down) from the y intercept until the next point that lies on the line and run is how far i need to go over from how many units i just went up. If u continue to go 8 up and 1 over from each point u will see that u get a point lying of the line. This is why 8/1 is your slope
8/1 is the slope and 0,0 is your y intercept so we put nothing
the equation is y=8x
Step-by-step explanation:
This is quite a complex problem. I wrote out a really nice solution but I can't work out how to put it on the website as the app is very poorly made. Still, I'll just have to type it all in...
Okay so you need to use a technique called logarithmic differentiation. It seems quite unnatural to start with but the result is very impressive.
Let y = (x+8)^(3x)
Take the natural log of both sides:
ln(y) = ln((x+8)^(3x))
By laws of logarithms, this can be rearranged:
ln(y) = 3xln(x+8)
Next, differentiate both sides. By implicit differentiation:
d/dx(ln(y)) = 1/y dy/dx
The right hand side is harder to differentiate. Using the substitution u = 3x and v = ln(x+8):
d/dx(3xln(x+8)) = d/dx(uv)
du/dx = 3
Finding dv/dx is harder, and involves the chain rule. Let a = x+ 8:
v = ln(a)
da/dx = 1
dv/da = 1/a
By chain rule:
dv/dx = dv/da * da/dx = 1/a = 1/(x+8)
Finally, use the product rule:
d/dx(uv) = u * dv/dx + v * du/dx = 3x/(x+8) + 3ln(x+8)
This overall produces the equation:
1/y * dy/dx = 3x/(x+8) + 3ln(x+8)
We want to solve for dy/dx, achievable by multiplying both sides by y:
dy/dx = y(3x/(x+8) + 3ln(x+8))
Since we know y = (x+8)^(3x):
dy/dx = ((x+8)^(3x))(3x/(x+8) + 3ln(x+8))
Neatening this up a bit, we factorise out 3/(x+8):
dy/dx = (3(x+8)^(3x-1))(x + (x+8)ln(x+8))
Well wasn't that a marathon? It's a nightmare typing that in, I hope you can follow all the steps.
I hope this helped you :)
