A = P( 1 + rt)
A/P = 1 + rt
A/P - 1 = rt
t = (( A/P)) - 1)/r
t = (( 5500/1000) - 1)/(6.25/100
t = (5.5 - 1)/0.0625
t = 4.5/0.0625 = 72 years
Answer it will take 72 Years...
Hope it helps!!!!!
Answer:

Step-by-step explanation:
The most straightforward way is direct substitution of g(x) for x in f(x):

<span><u><em>The correct answers are: </em></u>
1) A;
2) A;
4) D
3 cannot be done because the graph is not shown.
<u><em>Explanation:</em></u><span><u><em> </em></u>
1) Shifting a graph to the left, we would normally think of subtracting 1 from the function. However, horizontal translations are the opposite; left means adding 1 to x, while right means subtracting 1 from x.
2) A reflection in the x-axis means the y-coordinate will be negated (the opposite sign). This means that g(x)=-f(x)=-(x^2+5=-x^2-5.
4) To perform a vertical stretch of a function, we multiply by the factor; this gives us y=6x.</span></span>
hey sorry I need a free point !
Answer:
Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.
Step-by-step explanation:
The equation f(x) given is:

For x = 0. the value of the expression is:

For x = 1, the value of the expression is:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.
In other words, there is at least one solution for the equation between x=0 and x=1.