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vovangra [49]
3 years ago
14

A tour company has a boat that sits at most 40 passengers. For a cruise on the Hudson River they charge $12 per adult and $5 per

child. They will only take the boat out if they have sold at least $250 worth of tickets. Let a be the number of adults who take the cruise and c be the number of children. Will they take the boat out if they 14 adults and 9 children buy tickets? Justify.
Mathematics
1 answer:
EleoNora [17]3 years ago
5 0

Answer:

No

Step-by-step explanation:

For the adults:

$12 times the 14 adults which is: $168

Then for the kids:

$5 times the 9 kids which is: $45

Add next:

$168 plus the $45 equals $213

A(14)+b(5)=c

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yes because you have to pay more it's tricky

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{(-1, 2), (0, 2), (5, 2)} is a function.
gayaneshka [121]

The relation is a function.

Step-by-step explanation:

As there is only one y-value for every x-value, this is a function

4 0
2 years ago
PLEASE HELP!!! TRIG, Theres a picture!!
BartSMP [9]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

3(  { \tan }^{2} \theta -    { \sec }^{2}  \theta)

Using trigonometric identities

That's

1 + { \tan }^{2} \theta  =   { \sec }^{2}  \theta

Rewrite the expression

That's

3({ \tan }^{2} \theta - (1 + { \tan }^{2} \theta)) \\

Simplify

We have

3({ \tan }^{2} \theta - 1 - { \tan }^{2} \theta) \\ 3({ \tan }^{2} \theta - { \tan }^{2} \theta - 1)

So we have

3( - 1)

We have the final answer as

<h2>- 3</h2>

Hope this helps you

3 0
3 years ago
The ratio of blue jays to Robin's was 6 to 7. If there were 84 Robins, how many blue jays were there?​
Paul [167]

Answer:

72

Step-by-step explanation:

<em>Since the ratio of blue jays to robin's was 6 to 7 then if there were 84 robins how many blue jays were there.</em>

<em>6 to 7 can also be express as 6/7</em>

<em>Thus, we can set up a proportion</em>

<em>6/7 = x/84</em>

<em>Now, we have to solve for x</em>

<em>x = 72</em>

<em>Hence, if there were 84 robin there would be 72 blue jays.</em>

<em />

<u><em>~lenvy~</em></u>

3 0
2 years ago
PLEASE HELP
notsponge [240]

Answer:

(a)

x cubed is

=x^3=x3

5 times the cube of x is

=5x^3=5x3

4 times x is

=4x=4x

the quotient of 4 times x and 3 is

=\frac{4x}{3}=34x

so,

the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 is

=5x^3-\frac{4x}{3}=5x3−34x ..........Answer

(b)

5 times cube of x is

=5x^3=5x3

5 times cube of x divided by 4 times x is

=\frac{5x^3}{4x}=4x5x3 ..........Answer

(c)

difference of 5 times x cube and 4 is

=5x^3 -4=5x3−4

so,

the quotient of the difference of 5 times x cube and 4 and x is

=\frac{5x^3-4}{x}=x5x3−4 ...........Answer

(d)

difference of 5 times x and 4 is

=5x-4=5x−4

so,

the cube of the difference of 5 times x and 4 is is

=(5x-4)^3=(5x−4)3 ............Answer

5 0
3 years ago
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