The percentage yield of the oxygen gas is 60%.
<h3>What is the limiting reactant?</h3>
The reaction equation is;
2H^+ + H2O2 + 2MnO4 -> 2MnO2 + 4H2O + 3O2
Number of moles of hydrogen peroxide = 30/1000 * 0.30 M = 9 * 10^-3 moles
Number of moles of potassium permanganate = 30/1000 * 0.30 M = 9 * 10^-3 moles
Now;
1 mole of H2O2 reacts with 2 moles of permanganate
9 * 10^-3 moles of H2O2 reacts with 9 * 10^-3 moles * 2 moles/1 mole
= 1.8 * 10^-2 moles
Hence, permanganate is the limiting reactant
b) The theoretical yield of oxygen is;
2 moles of oxygen produced 3 moles of O2
9 * 10^-3 moles oxygen produced 9 * 10^-3 moles * 3 moles/2 moles
= 0.0135 moles
If 1 mole of O2 occupies 22.4 L
0.0135 moles of O2 occupies 0.0135 moles * 22.4 L/ 1 mole
= 0.302 L or 302 mL
c) Percentage yield of oxygen = 178 mL/ 302 mL * 100/1
= 60%
Learn more about percentage yield:brainly.com/question/27492865
#SPJ1
