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2 years ago

PLEASE HELP!!!

Chemistry

1 answer:

poizon [28]2 years ago

6 0

The net ionic equation of the reaction is:

Pb²⁺ (aq) +2 I⁻ (aq) → PbI2(s)

<h3>What are net ionic equations?</h3>

Net ionic equations are equations where ions which remain in solution known as spectator ions are not shown in the equation. Only ions involved in formation of product are shown.

In the given equation, sodium and nitrate ions are spectator ions.

The net ionic equation of the given reaction is as follows:

Pb²⁺ (aq) +2 I⁻ (aq) → PbI2(s)

In conclusion, spectator ions are not shown in net ionic equation.

Learn more about net ionic equations at: brainly.com/question/19705645
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Calculate the ph of a solution formed by mixing 200.0 ml of 0.30 m hclo with 300.0 ml of 0.20 m kclo. the ka for hclo is 2.9 × 1

velikii [3]

C(HClO) = 0,3 M.
V(HClO) = 200 mL = 0,2 L.
n(HClO) = c(HClO) · V(HClO).
n(HClO) = 0,06 mol.
c(KClO) = 0,2 M.
V(KClO) = 0,3 L.
n(KClO) = 0,06 mol.
V(buffer solution) = 0,2 L + 0,3 L = 0,5 L.
ck(HClO) = 0,06 mol ÷ 0,5 L = 0,12 M.
cs(KClO) = 0,06 mol ÷ 0,5 L = 0,12 M.
Ka(HClO) = 2,9·10⁻⁸.
This is buffer solution, so use Henderson–Hasselbalch equation:
pH = pKa + log(cs ÷ ck).
pH = -log(2,9·10⁻⁸) + log(0,12 M ÷ 0,12 M).
pH = 7,54 + 0.
pH = 7,54

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Letter (f) represents the heat of reaction of both the reverse and the forward reaction.

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Thus, for the forward reaction, the change in enthalpy, or ΔH rxn, is the arrow labeled (f):

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$\Delta H_{rxn}=\Delta H_{X+Y}-\Delta H_Z$

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