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Cloud [144]
2 years ago
9

PLEASE HELP!!!

Chemistry
1 answer:
poizon [28]2 years ago
6 0

The net ionic equation of the reaction is:

  • Pb²⁺ (aq) +2 I⁻ (aq) → PbI2(s)

<h3>What are net ionic equations?</h3>

Net ionic equations are equations where ions which remain in solution known as spectator ions are not shown in the equation. Only ions involved in formation of product are shown.

In the given equation, sodium and nitrate ions are spectator ions.

The net ionic equation of the given reaction is as follows:

  • Pb²⁺ (aq) +2 I⁻ (aq) → PbI2(s)

In conclusion, spectator ions are not shown in net ionic equation.

Learn more about net ionic equations at: brainly.com/question/19705645
#SPJ1

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A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31
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The volume of the gas will be 78.31 L at 1.7 °C.

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We can find the temperature of the gas by the ideal gas law equation:

PV = nRT

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V: is the volume

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R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles

Now, we can find the temperature with the final conditions:

T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K

The temperature in Celsius is:

T_{2} = 274.7 - 273 = 1.7 ^{\circ} C

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!            

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