Select the correct answer.

Interactive LearningWare 4.1 reviews the approach taken in problems such as this one. A 1800-kg car is traveling with a speed of

Lubov Fominskaja [6]

Answer:

F= 4788 N

Explanation:

Because the car moves with uniformly accelerated movement we apply the following formula:

vf²=v₀²+2*a*d Formula (1)

Where:

d:displacement in meters (m)

v₀: initial speed in m/s

vf: final speed in m/s

a: acceleration in m/s²

Data

d=36.9 m

v₀=14.0 m/s m/s

vf= 0

Calculating of the acceleration of the car

We replace dta in the formula (1)

vf²=v₀²+2*a*d

(0)²=(14)²+2*a*(36.9)

-(14)²= (73.8) *a

a= - (196) / (73.8)

a= - 2.66 m/s²

Newton's second law of the car in direction horizontal (x):

∑Fx = m*ax Formula (2)

∑F : algebraic sum of the forces in direction x-axis (N)

m : mass (kg)

a : acceleration (m/s²)

Data

m=1800 Fkg

a= - 2.66 m/s²

Magnitude of the horizontal net force (F) that is required to bring the car to a halt in a distance of 36.9 m :

We replace data in the formula (2)

-F= (1800 kg) * ( -2.66 m/s² )

F= 4788 N

6 0

3 years ago

Lunar missions have revealed that the moon has:

myrzilka [38]

That the moon has soil within its shadowy craters rich and useful material

5 0

3 years ago

A golf ball is whacked in a direction 25 degrees south of the east axis. The ball travels 125m. What are the east and north comp

Natalka [10]

We are given:

Direction of motion: 25 degrees south of the east axis

Distance covered = 125 m

East component of the Ball:

this component is denoted by green color in the image

Once we drop a perpendicular from the end of the direction vector on the x-axis, we get a right angled triangle

The magnitude of the side of the triangle on the x-axis denotes the east component of the ball

Using trigonometry, we find that the east component of the ball is:

125 * Cos(25 degrees)

125 * 0.9 = 112.5 i (here, i denotes rightward direction on the x-axis)

North Component of the Ball:

this component is denoted by blue color in the image

Using trigonometry, we find that the North component of the ball is:

125* Sin(25 degrees) (-j) [j denotes upward movement on the y-axis, since the vector is acting downwards, we have used '-j']

125 * 0.42 (-j)

52.5 (-j) = -52.5 j

Therefore the direction vector of the ball is 112.5 i - 52.5 j

where 112.5 i is the East Component and -52.5 is the North Component

3 0

3 years ago

An object is allowed to fall freely near the surface of a planet. The object has an acceleration due to gravity of 24 m/s2. How

Alborosie

Answer:

12 m

Explanation:

The object is in uniformly accelerated motion, so the distance covered can be found using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance

u is the initial velocity

t is the time

a is the acceleration

For this problem,

$g=24 m/s^2$

and

u = 0, since we are considering the first second of motion

So, substituting t = 1 s, we find

$s=0+\frac{1}{2}(24)(1)^2=12 m$

6 0

4 years ago

Water is flowing in a fire hose with a velocity of 1.0 m/s and a pressure of 200000 Pa. At the nozzle the pressure decreases to

jeka57 [31]

Answer:

The velocity is $v_n =14.09 \ m/s$

Explanation:

From the question we are told that

The velocity of the water in the pipe is $v_i = 1.0 \ m/s$

The pressure inside the pipe is $P_i = 200000 \ Pa$

The pressure at the nozzle is $P_n = 101300 \ Pa$

The density of water is $\rho = 1000 \ kg / m^3$

For the height $h_1 = h_2 = h$

where $h_1$ is height of water in the pipe

and $h_2$ is height of water at the nozzle

Generally Bernoulli equation is represented as

$\frac{1}{2} \rho * v_i ^2 + \rho * g * h_1 + P_i = \frac{1}{2} \rho v_n ^2 + \rho * g* h_2 + P_n$

=> $\frac{1}{2} \rho * v_i ^2 + \rho * g * h + P_1 = \frac{1}{2} \rho v_n ^2 + \rho * g* h + P_2$

Where $v_n$ is the velocity of the water at the nozzle

Now making $v_n$ the subject

$v_n = \sqrt{\frac{2}{\rho} [ P_i - Pn + \frac{1}{2} \rho v_i^2}$

substituting values

$v_n = \sqrt{\frac{2}{1000} [ 200000 - 101300 + \frac{1}{2} (1000 * (1.0)^2)}$

$v_n =14.09 \ m/s$

6 0

4 years ago