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3 years ago

ਨਿਰਭਰ ਕਰਦੀਇਬਾਣੀ ਸਰੀਰਜ ਸਮੱਰਥਾ ਜਿਹੜਾ ਕਿੰ- ਉਨ ਬਾਦ ਤੇ

Physics

1 answer:

kipiarov [429]3 years ago

6 0

Answer:

I can't understand

Explanation:

But if you have a english translator I can help

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Can somebody help me on this mcq question?

andrew11 [14]

A) lighting an electric lamp as it becomes darker

3 0

3 years ago

A 25.0-kg child is standing at the edge of a horizontal merry-go-round with a radius of 2.40 m and a moment of inertia of 356 kg

motikmotik

Answer:

$\omega_{f}=1.634\ rad/s$

Explanation:

given,

diameter of merry - go - round = 2.40 m

moment of inertia = I = 356 kg∙m²

speed of the merry- go-round = 1.80 rad/s

mass of child = 25 kg

initial angular momentum of the system

$L_i = I\omega_i$

$L_i =356\times 1.80$

$L_i =640.8\ kg.m^2/s$

final angular momentum of the system

$L_f = (I_{disk}+mR^2)\omega_{f}$

$L_f = (356 + 25\times 1.2^2)\omega_{f}$

$L_f= (392)\omega_{f}$

from conservation of angular momentum

$L_i = L_f$

$640.8= (392)\omega_{f}$

$\omega_{f}=1.634\ rad/s$

8 0

3 years ago

Read 2 more answers

you ride a bike for 2 hours at 25 km/hr then 3 hours at 34 km/hr. what is your average velocity (in km/hr)?

mamaluj [8]

<h3>Answer:</h3>

30.4 km/hr

<h3>Explanation:</h3>

<u>We are given</u>;

Speed in the first 2 hours as 25 km/hr
Speed in the next 3 hours as 34 km/hr

We are required to determine the average velocity in km/hr

To get the average velocity we divide total distance by total time.
Thus, we need to determine the total distance

Distance = Speed × time

Distance covered in the first 2 hours;

= 25 km/hr × 2 hours

= 50 km

Distance in the next 3 hours

= 34 km/hr × 3 hours

= 102 km

Therefore, total distance = 50 km + 102 km

= 152 km

Total time = 2 hrs + 3 hrs

= 5 hours

Therefore;

Average speed = 152 km ÷ 5 hours

= 30.4 km/hr

Thus, the average speed is 30.4 km/hr

4 0

3 years ago

The property of our eyes that makes us perceives a rotating coloured disc as white.

tatuchka [14]

Uh Wait what? Explain

7 0

3 years ago

A rotating wheel requires 5.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 rad/

torisob [31]

Answer:

The constant angular acceleration of the wheel is 12.16 rad/s²

Explanation:

Given;

initial angular distance, θ = 28

time of the motion, t = 5 s

initial angular velocity is calculated as;

$\omega _i = \frac{\theta}{t} = \frac{28}{5}.\frac{rev}{s} \ \times \ \ \frac{2 \pi \ rad}{1 \ \ rev} = 35.19 \ rad/s$

final angular velocity is given as, $\omega _f = 96.0 \ rad/s$

The constant angular acceleration is calculated as;

$\alpha = \frac{\omega _f - \omega _i}{t} \\\\\alpha = \frac{96 - 35.19}{5} \\\\\alpha = 12.16 \ rad/s^2$

Therefore, the constant angular acceleration of the wheel is 12.16 rad/s²

6 0

3 years ago

ਨਿਰਭਰ ਕਰਦੀਇਬਾਣੀ ਸਰੀਰਜ ਸਮੱਰਥਾ ਜਿਹੜਾ ਕਿੰ- ਉਨ ਬਾਦ ਤੇ​

ਨਿਰਭਰ ਕਰਦੀਇਬਾਣੀ ਸਰੀਰਜ ਸਮੱਰਥਾ ਜਿਹੜਾ ਕਿੰ- ਉਨ ਬਾਦ ਤੇ