Answer:
3.97305 m
Explanation:
a = Acceleration due to gravity = 9.81 m/s²
If a jump lasts for 1.8 seconds this means that from the moment when the person leaves the ground till the person touches the ground again it takes 1.8 seconds. So, maximum height reached will be at half the time of the jump i.e., 0.9 seconds.
u = Initial velocity = 0
Equation of motion

So, height of the jump is 3.97305 m.
Answer:
The mass of air in the box is 0.78 grams.
Explanation:
A litre equals a cubic decimetre. By definition of density (
), in grams per litre, we calculate the mass of air inside the cube (
), in grams:
(1)
Where
is the volume occupied by air within the cube, in litres.
If we know that
and
, then the mass of air is:


The mass of air in the box is 0.78 grams.
Answer:
0.05806
Explanation:
= Mass of asteroid x
= Mass of asteroid y
= Distance from asteroid x = 140 km
= Distance from asteroid y = 581 km
m = Mass of asteroid
Force of gravity between asteroid x and the astronaut

Force of gravity between asteroid x and the astronaut

Here these two forces are equal as they are in equilibrium

The ratio of the masses of the asteroid is 0.05806
Answer:
1250m
Explanation:
Since it's a Constant Velocity, and not an acceleration rate, simple math. 150*5=750+500=1250m.
Answer:
True
Explanation:
Scientists and professionals in health sciences are invited to participate in congresses, conferences and events. Communications to conferences can be of different types, but it is always necessary to draw a table with the contents that you want to present.
Due to the rise and importance of conferences in recent years, scientists and scientific societies that provoke conferences have gained greater knowledge of the importance of defining their publications, so that the problems related to these issues are becoming smaller .
It is important to know how to write the communication and if the conference proceedings or reports will be considered as primary publication, then it is recommended to prepare the manuscript in the same style as the journal articles. For this it is recommended to use the same method.