1) Vf = Vo - gt; Vf = 0 => Vo = gt = 9.8m/s^2 * 1.5s = 14.7 m/s
2) d = Vo*t - gt^2 /2 = 14.7m/s*1.5 - 9.8m/s^2 * (1.5s)^2 / 2 = 11.02 m
15+3=18km/hour
Think about it like this. The boat is going 15 faster than the river, and the river is going 3 faster than the bank, so the boat is going 18 faster than the river bank
It will be
d=m/v
=10/2
=5g/ml
Answer:
8.049 MW
Explanation:
The expression for gravitational potential energy is given as
Ep = mgh............. Equation 1
Ep = gravitational potential energy, m = mass of water, h = height, g = acceleration due to gravity.
Given: m = 58.4×10³ kg, h = 20.1 m, g = 9.81 m/s²
Substitute into equation 1
Ep = 58.4×10³(20.1)(9.81)
Ep = 1.6098×10⁷ J.
If one half the gravitational potential energy of the water were converted to electrical energy
Electrical energy = Ep/2
Electrical energy = (1.6098×10⁷)/2
Electrical energy = 8.049×10⁶ J
In one seconds,
The power generated = 8.049×10⁶ W
Power generated = 8.049 MW
