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kirill [66]
3 years ago
7

What is the formula for newton's third law of motion​

Physics
2 answers:
dem82 [27]3 years ago
8 0

Answer:

The third law states that all forces between two objects exist in equal magnitude and opposite direction: if one object A exerts a force FA on a second object B, then B simultaneously exerts a force FB on A, and the two forces are equal in magnitude and opposite in direction: FA = −FB.

Explanation:

You can literally google this. It would have been faster.

tensa zangetsu [6.8K]3 years ago
8 0
The formula would be Fa = -Fb
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The formula for weight is always weight=mass X gravitational field strength.
We already know the mass is 75kg.
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Weight is measured on Neutons as it is a force.
8 0
2 years ago
Two children of about the same weight are playing at the playground. They both climb up to the top of a small tower. One slides
olya-2409 [2.1K]

Answer:

D

Explanation:

D) The overall work done by gravity is zero  

This statement is correct .

If m be the mass of each of the children and h be the height of tower

work done by gravity on the boys in going up = - mgh

it is so because force applied by gravity = mg downwards and displacement

is upwards

work done will be negative = - mgh

Work done by gravity on boys when they come down = + mgh because both force and displacement are downwards .

Hence total work done = - mgh + mgh = 0.

The children will have same kinetic energy as the inclined surface is friction-less so no energy will be dissipated hence addition of energy to boys in both the cases will be same.

4 0
3 years ago
Find the net force for <br> 10 N<br> 10 N<br> 25degree<br> 5N<br> 5N
icang [17]

Answer:

30n

Explanation:

7 0
2 years ago
In this diagram, which force is represted by L?
Dmitry [639]
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8 0
3 years ago
An airplane pilot sets a compass course due west and maintains a speed of 220 km/h. after flying for a half hour she finds herse
timurjin [86]

The net speed due west is = distance traveled in west / time taken = 120/0.5 = 240 km/h.  

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the angle of airspeed south of west is tan⁻¹ ( airspeed due south / airspeed due west )= tan⁻¹(40/20)=63.43 degrees.  

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so component west = sqrt ( 220^2 - 40^2 ) = 216.33 km/h.  

the angle north of west is arctan( 40/216.33 ) = 10.47 degrees.

5 0
2 years ago
Read 2 more answers
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