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dybincka [34]
3 years ago
8

The two blocks shown below have masses m1 = 400 g and m2 = 600 g. They are connected by a string and lie on a frictionless table

top. A 3.5 N force is applied to block m2, pulling it to the right. Find the acceleration then find the tension force in the string between two objects
Physics
1 answer:
Effectus [21]3 years ago
4 0
Answer is X^\12+13/2
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4 years ago
Read 2 more answers
A 5000 kg truck traveling at 60 m/s stops in 5 seconds. How much friction was between the truck's tires and the ground? ​
oksano4ka [1.4K]

Answer:

60000N

Explanation:

acceleration is change in velocity

a =(v-u)/t where a is acceleration u is initial velocity and v is final velocity

a = (0-60)/5 = -60/5= - 12m/s^2

here minus sign shows that body is decelerating and force is  force of friction Now f = ma here f is force of friction m is mass and a is acceleration

f= 5000×- 12= -60000N

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8 0
4 years ago
See attachment for the question
Zarrin [17]

The acceleration of the body is provided by the tension in the rope.

<h3>What is centripetal acceleration?</h3>

The centripetal acceleration is given by a = v^2/r. v = velocity of the body, r = radius

a = (8.40 m/s)^2/(8.50 m)

a = 8.3 m/s^2

The tension in the rope is the force that provides the centripetal force in the rope.

Learn more of centripetal acceleration:brainly.com/question/14465119

#SPJ1

6 0
2 years ago
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