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yan [13]
3 years ago
11

How long is a guy wire reaching from the top of a 6ft. Pole to a point on the ground 4ft. From the pole

Mathematics
1 answer:
LenKa [72]3 years ago
5 0

Answer:

The guy wire is 7.2111 ft long

Step-by-step explanation:

Notice that we are in the presence of a right angle triangle formed by: the height (the standing 6 ft pole), the base (the distance from the pole to the anchoring point on the ground), and the actual guy wire. See attached image for reference.

Notice that since pole and ground are perpendicular to each other (at 90 degrees) , the guy wire forms what is called the "hypotenuse" (longest side) of the right angle triangle. We can therefore use the Pythagorean Theorem to solve this problem with the formula for the hypotenuse:

Hypotenuse=\sqrt{side1^2 +side2^2} \\Hypotenuse= \sqrt{6^2+4^2}\\Hypotenuse=\sqrt{36+16} \\Hypotenuse=\sqrt{52} \\Hypotenuse=7.2111\, ft

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Mars2501 [29]

For this case we have a direct variation of the form:

f (x) = kx

Where "k" is the constant of proportionality. To find it, we use the following data:

f (x) = 40\ and\ x = 8

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Thus, the direct variation is given by:

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Forx = 2 we have:

f (2) = 5 * 2\\f (2) = 10

Answer:

The value of the direct variation for x = 2is: f (2) = 10


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3 years ago
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