How long is a guy wire reaching from the top of a 6ft. Pole to a point on the ground 4ft. From the pole
1 answer:
Answer:
The guy wire is 7.2111 ft long
Step-by-step explanation:
Notice that we are in the presence of a right angle triangle formed by: the height (the standing 6 ft pole), the base (the distance from the pole to the anchoring point on the ground), and the actual guy wire. See attached image for reference.
Notice that since pole and ground are perpendicular to each other (at 90 degrees) , the guy wire forms what is called the "hypotenuse" (longest side) of the right angle triangle. We can therefore use the Pythagorean Theorem to solve this problem with the formula for the hypotenuse:
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Answer:
9.93
Step-by-step explanation:
Secant-Tangent theorem tells us that the product of the secant segment with its external segment is equal to the square of the tangent segment.
From the diagram, we can say (let the unknown part of secant line, the part left of the segment length 5, be y):
(15+y)(10) = 17^2
Solving for y we get:
Now we can use the chord theorem to solve for x. Chord theorem tells us that when 2 intersecting chords create 4 segments, the product of the individual chord segments are equal. Thus we can say:
5 * 13.9 = 7 * x
Now solving, we get:
Thus x = 9.93
last answer choice is right.