For this case we have a direct variation of the form:

Where "k" is the constant of proportionality. To find it, we use the following data:

Substituting:

Clearing the value of k:

Thus, the direct variation is given by:

For
we have:

Answer:
The value of the direct variation for
is: 
The '40 years' is not part of the question. It's just there to prove that
'2% each year' has been the experience for the past 40 years, so it's
a good number to use for the rate of growth, past or future.
So, at any number of years 'Q' after the beginning of "this period",
the population was or will be
Pop = (220,000) (1.02)^Q power.
(This equation is familiar from all of the bank-interest problems
the student has done in past math classes.)
In 10 years after the beginning of "this period",
Pop = (220,000) (1.02)¹⁰ = <em>243,800 </em>(or any reasonably close number)
Answer:
70000 gallons
Step-by-step explanation:
The total time between 8 a.m. to 6 p.m is 10 hours. The company starts producing at 8 am, therefore the time from 8 am to noon (that is 12 p.m) is 4 hours.
Since clients demand 100,000 gallons of milk over the course of one day, the demand of milk per hour = total demand per day/ total time per day
Demand per hour = 100000 gallons / 10 hours = 10000 gallons per hour
Since the milk is processed at a fixed rate of 7500 gallons/hour, At noon the amount of of milk produced = 7500 gallons/hour × 4 hours = 30000 gallons.
The gallons of milk are in the queue to be processed at noon = 100000 gallons - 30000 gallons = 70000 gallons
A. the position of the figure changes