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kozerog [31]
3 years ago
14

A blue jay lives in a nest that is 12 meters high in a tree the blue jay flies 15 meters to get from its nest to a flower on the

ground how far is the flower from the base of the tree

Mathematics
1 answer:
Ivan3 years ago
8 0

Answer:

The distance between the base of the tree and the flower is 9m

Step-by-step explanation:

Here, we have to paint a picture.

The flower is on the ground, the height of the tree is 12m.

The distance from the nest to the flower on the floor is 15m

Indisputably, what we have is a right angled triangle, with the height being 12m, the length of the hypotenuse being 15 and we are asked to calculate the adjacent which represents the distance from the base of the tree to the flower

To get this distance, we simply apply the Pythagoras’ theorem which states that the square of the hypotenuse(longest side of the triangle) is equal to the sum of the squares of the other two sides.

Thus mathematically, we know that our hypotenuse is 15m and the height is 12m

The length we are to calculate is the adjacent and it is equal to;

15^2 - 12^2

= 225 - 144

= 81

The length is thus

√(81) = 9m

Please check attachment for a diagrammatic picture of the triangle

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Typing errors in a text are either nonword errors (as when "the" is typed as "teh") or word errors that result in a real but inc
nordsb [41]

Answer:

a) X is binomial with n = 10 and p = 0.3

Y is binomial with n = 10 and p = 0.7

b) The mean number of errors caught is 7.

The mean number of errors missed is 3.

c) The standard deviation of the number of errors caught is 1.4491.

The standard deviation of the number of errors missed is 1.4491.

Step-by-step explanation:

For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

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The expected value of the binomial distribution is:

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The standard deviation of the binomial distribution is:

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10 word errors.

This means that n = 10

(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

So for Y, p = 0.7.

The answer is:

Y is binomial with n = 10 and p = 0.7

(b) What is the mean number of errors caught?

E(Y) = np = 10*0.7 = 7

The mean number of errors caught is 7.

What is the mean number of errors missed?

E(X) = np = 10*0.3 = 3

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491

The standard deviation of the number of errors missed is 1.4491.

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So you said 20% is xx???
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