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Lesechka [4]
1 year ago
7

Need help on this one please

Mathematics
1 answer:
lesya [120]1 year ago
3 0

Answer: y = -2x - 4

Step-by-step explanation:

This question asks that you give your answer in slope-intercept form, which is written as y = mx + b, where m is the slope, and b is the y-intercept.


In order to write an equation for this line in slope-intercept form, you need to find the slope and the y-intercept. You can find the slope by selecting any two clear points on the graph and finding the [change in y] ÷ [change in x].

For example, I’ll use (-3, 2) and (-2, 0):

Change in y: 2 - 0 = 2

Change in x: -3 - (-2) = -1

Change in y ÷ Change in x = 2 ÷ (-1) = -2


So, the slope, m, is -2. Finding b, or the y-intercept is a lot more straightforward; you just find where the line intercepts the y-axis, or when x = 0. Looking at the graph, we can see that the y-intercept is -4, so b = -4.


Now, we can put these together in an equation.

y = mx + b, where m = -2 and b = -4


y = -2x -4

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a. The expression for the tension in the string is T = mg

b. The expression for the tension in the chain is T = 2mg

To solve the problem, we need to know what tension is.

<h3>What is tension?</h3>

This is the opposing force in a stretched material.

<h3>a. Tension in the string</h3>

The expression for the tension in the string is T = mg

Since the string supports the weight of the object, the tension in the string equals the weight of the particle.

Let

  • T = tension in sring and
  • W = weight of particle = mg where
  • m = mass of particle and
  • g = acceleration due to gravity

So, T = W

T = mg

So, the expression for the tension in the string is T = mg

<h3>b. Tension in chain</h3>

The expression for the tension in the chain is T = 2mg

<h3 />

Since the chain supports both strings, the tension in the chain equals the tension in both strings.

Let

  • T' = tension in chain and
  • T = tension in each string

So, T' = T + T

T' = 2T

T' = 2W

T' = 2mg

So, the expression for the tension in the chain is T = 2mg

<h3 />

Learn more about tension here:

brainly.com/question/24994188

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