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Lesechka [4]
2 years ago
7

Need help on this one please

Mathematics
1 answer:
lesya [120]2 years ago
3 0

Answer: y = -2x - 4

Step-by-step explanation:

This question asks that you give your answer in slope-intercept form, which is written as y = mx + b, where m is the slope, and b is the y-intercept.


In order to write an equation for this line in slope-intercept form, you need to find the slope and the y-intercept. You can find the slope by selecting any two clear points on the graph and finding the [change in y] ÷ [change in x].

For example, I’ll use (-3, 2) and (-2, 0):

Change in y: 2 - 0 = 2

Change in x: -3 - (-2) = -1

Change in y ÷ Change in x = 2 ÷ (-1) = -2


So, the slope, m, is -2. Finding b, or the y-intercept is a lot more straightforward; you just find where the line intercepts the y-axis, or when x = 0. Looking at the graph, we can see that the y-intercept is -4, so b = -4.


Now, we can put these together in an equation.

y = mx + b, where m = -2 and b = -4


y = -2x -4

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Where is the line

Step-by-step explanation:

3 0
3 years ago
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A regular hexagon has sides of 3 feet. What is the area of the hexagon?
frosja888 [35]

Answer:

13.5\sqrt{3}\:\text{ft}^{2}

Step-by-step explanation:

Given: The side of a regular hexagon is 3 feet.

To find: Area of the hexagon

Solution:

It is given that the side of a regular hexagon is 3 feet.

We know that the area of a regular hexagon whose side is a units is \frac{3\sqrt{3} }{2} a^{2}

Here, the side is 3 feet

So, area of the regular hexagon

=\frac{3\sqrt{3} }{2} \times3^{2}

=\frac{3\sqrt{3} }{2} \times9

=\frac{27\sqrt{3} }{2}

=13.5\sqrt{3}\:\text{ft}^{2}

Hence, area of the regular hexagon is 13.5\sqrt{3}\:\text{ft}^{2}

6 0
3 years ago
The length of the diagonal of a rectangle is 140−−−√ inches.
andrew11 [14]

Answer:

answer is second one

Step-by-step explanation:

The length is between 11 and 12 inches.

√140 = 11.83 inches

5 0
3 years ago
A line m is perpendicular to an angle bisector of ∠A. The sides of ∠A intersect this line m at points M and N. Prove that △AMN i
Ray Of Light [21]

Answer:


Step-by-step explanation:

<em><u>Given</u></em><u>:</u>       A line m is perpendicular to the angle bisector of ∠A. We call this  

                 intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.

                 AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.

<u><em>To Prove</em></u>:   <em><u>ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are</u></em>

<em>                    </em><em><u>equal. </u></em>

<em><u>Solution</u></em>:  Now, In ΔADM and ΔADN

                 ∠MAD=∠NAD     ...(1) (∵Given)

                  AD=AD                ...(2) (∵common side)

                  ∠ADM=∠ADN     ...(3) (∵Given)

                  <u><em> Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN</em></u>

                                                         ( ∵ ASA  congruence rule)

                  ⇒<u><em> AM=AN</em></u>

                  Now, In Δ AMN

                 AM=AN (∵ Proved)

                  Hence, ΔAMN is an isosceles  triangle.


7 0
3 years ago
I really need help this is my second time......
KIM [24]
First find the area of the triangle,
(8.4 x 24)/2 = 100.8
Then find the area of the parallelogram,
24 x 12 = 288

Then add both,
100.8+288 = 388.8 yd^2
7 0
4 years ago
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