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2 years ago

If the change of enthalpy of this reaction when proceeding left to right is +14 kcal, which chemical equation is correct?

Chemistry

1 answer:

bagirrra123 [75]2 years ago

7 0

Answer:

N₂O₄ + 14 kcal ⇄ 2NO₂.

Explanation:

Since the sign of ΔH determines either the reaction is exothermic or endothermic:

+ve, the reaction is endothermic.

-ve, the reaction is exothermic.

∵ The change of enthalpy of this reaction when proceeding left to right is + 14 kcal (+ ve sign).

∴ The reaction is endothermic, the heat is a part of the reacatnts in the reaction.

So, the reaction is:

N₂O₄ + 14 kcal ⇄ 2NO₂.

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2 years ago

Given the balanced equation, 2 H2 + O2 -> 2 H2O, answer the following

9966 [12]

Answer: $O_2$ is the limiting reagent

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} H_2=\frac{10.0g}{2g/mol}=5.00moles$

$\text{Moles of} O_2=\frac{20.0g}{32g/mol}=0.625moles$

The balanced chemical reaction is :

$2H_2+O_2\rightarrow 2H_2O$

According to stoichiometry :

1 moles of $O_2$ require = 2 moles of $H_2$

Thus 0.625 moles of $O_2$ will require= $\frac{2}{1}\times 0.625=1.25moles$ of $H_2$

Thus $O_2$ is the limiting reagent as it limits the formation of product and $H_2$ is the excess reagent as it is present more than the required amount.

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2 years ago