Answer:
63.36gallons
Explanation:
Given:
Volume of water used for dialysis = 2.4 x 10²L
Solution:
We are to convert from liters to gallons.
The conversion factor is shown below:
1L = 0.264gallons
To convert to litre:
since 1L = 0.264gallons
2.4 x 10²L = (2.4 x 10² x 0.264)gallons; 63.36gallons
Answer:
5.8μg
Explanation:
According to the rate or decay law:
N/N₀ = exp(-λt)------------------------------- (1)
Where N = Current quantity, μg
N₀ = Original quantity, μg
λ= Decay constant day⁻¹
t = time in days
Since the half life is 4.5 days, we can calculate the λ from (1) by substituting N/N₀ = 0.5
0.5 = exp (-4.5λ)
ln 0.5 = -4.5λ
-0.6931 = -4.5λ
λ = -0.6931 /-4.5
=0.1540 day⁻¹
Substituting into (1) we have :
N/N₀ = exp(-0.154t)----------------------------- (2)
To receive 5.0 μg of the nuclide with a delivery time of 24 hours or 1 day:
N = 5.0 μg
N₀ = Unknown
t = 1 day
Substituting into (2) we have
[5/N₀] = exp (-0.154 x 1)
5/N₀ = 0.8572
N₀ = 5/0.8572
= 5.8329μg
≈ 5.8μg
The Chemist must order 5.8μg of 47-CaCO3
Answer:
option C = 9.0 x 10²³ atoms
Explanation:
Data Given:
no. of moles of tin (Sn) atoms = 1.5 moles
no. of tin (Sn) atoms = ?
Solution:
Formula used to find number of atoms
no. of moles = no. of atoms / Avogadro's number
Rearrange the above equation:
no. of atoms = no. of moles x Avogadro's number . . . . . . (1)
Where
Avogadro's number = 6.022 x 10²³
Put values in equation 1
no. of atoms = 1.5 x 6.022 x 10²³
no. of atoms = 9.033 x 10²³
Round the figure = 9.0 x 10²³ atoms
So option C is correct
Answer:
The concentration of monosodium phosphate is 0.1262M
Explanation:
The buffer of H₂PO₄⁻ / HPO₄²⁻ (Monobasic phosphate and dibasic phosphate has a pKa of 7.2
To determine the pH you must use Henderson-Hasselbalch equation:
pH = pKa + log [A⁻] / [HA]
<em>Where [A⁻] is molarity of the conjugate base of the weak acid, [HA].</em>
For H₂PO₄⁻ / HPO₄⁻ buffer:
pH = 7.2 + log [HPO₄⁻² ] / [H₂PO₄⁻]
As molarity of the dibasic phosphate is 0.2M and you want a pH of 7.4:
7.4 = 7.2 + log [0.2] / [H₂PO₄⁻]
0.2 = log [0.2] / [H₂PO₄⁻]
1.58489 = [0.2] / [H₂PO₄⁻]
[H₂PO₄⁻] = 0.1262M
<h3>The concentration of monosodium phosphate is 0.1262M</h3>
<em />
Answer:
Option C = 4.25 g
Explanation:
Ounce and grams are unit of mass. Ounce is larger unit while gram is smaller unit. The one ounce is consist of 28.35 g or we can say that one ounce is equal to 28.35 g. In order to convert the given ounce value into grams the value is multiply with 28.35 g.
Given data:
Mass = 0.15 ounce
Mass in gram = ?
Solution:
One ounce is equal to 28.35 g, so
0.15 × 28.35 = 4.25 g