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Alborosie
3 years ago
9

During an experiment, solid iodine was placed in a sealed container. The container was gradually heated and purple-colored vapor

s of iodine formed were observed. Describe this system when it reaches phase equilibrium.
Chemistry
2 answers:
joja [24]3 years ago
6 0

Answer:The process is known as sublimation

Explanation:

Sublimation is a process wherby solid substances are changed into gaseous state

nexus9112 [7]3 years ago
6 0

Answer:

At equilibrium, solid iodine sublimes to give purple-coloured iodine vapour, which also condenses back to the solid iodine.

Explanation:

Sublimation is the process by which a solid changes state directly from the solid state to a gaseous state without going through the liquid state. Solid iodine is one of such solids that undergo sublimation.

  At equilibrium,            I₂ (solid)  ⇔  I₂(gaseous)

From the question,

As heat is gradually applied to the sealed container,  solid iodine begins to sublime and the purple-coloured vapour of iodine is observed.

As the heating continues, the intensity of the purple colour intensifies as more of the solid iodine undergoes sublimation.

At equilibrium however, it is observed that the intensity of the purple coloured iodine vapour remains the same.

This is so because at equilibrium, solid iodine sublimes to give purple-coloured iodine vapour, which also condenses back to the solid state

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How many atoms of Iodine are in a 12.75g sample of CaI2?
Inessa [10]

Answer is: 5.22·10²² atoms of Iodine.

m(CaI₂) = 12.75 g; mass of calcium iodide.

M(CaI₂) = 293.9 g/mol; molar mass of calcium iodide.

n(CaI₂) = m(CaI₂) ÷ M(CaI₂).

n(CaI₂) = 12.75 g ÷ 293.9 g/mol.

n(CaI₂) = 0.043 mol; amount of calcium iodide.

In one molecule of calcium iodide, there are two iodine atoms

n(I) = 2 · n(CaI₂).

n(I) = 0.086 mol; amount of iodine atoms.

Na = 6.022·10²³ 1/mol; Avogadro number.

N(I) = n(I) · Na.

N(I) = 0.086 mol · 6.022·10²³ 1/mol.

N(I) = 5.22·10²²; number of iodine atoms.

6 0
3 years ago
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How many moles of Si are in 78.0 grams of silicon
gladu [14]
The answer is 2.78 moles of Si

6 0
2 years ago
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A lime has a [H+] concentration of 0.0120 M.<br><br> What is the pH of the lime? 3 sig figs
Novosadov [1.4K]

Answer: pH= 1.92

Explanation:

pH= -log[H+]

pH= -log[0.012]

= 1.92

4 0
3 years ago
The first step in industrial nitric acid production is the catalyzed oxidation of ammonia. Without a catalyst, a different react
murzikaleks [220]

<u>Answer:</u> The value of K_{eq} is 4.84\times 10^{-5}

<u>Explanation:</u>

We are given:

Initial moles of ammonia = 0.0280 moles

Initial moles of oxygen gas = 0.0120 moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}

So, concentration of ammonia = \frac{0.0280}{1.00}=0.0280M

Concentration of oxygen gas = \frac{0.0120}{1.00}=0.0120M

The given chemical equation follows:

                  4NH_3(g)+3O_2(g)\rightleftharpoons 2N_2(g)+6H_2O(g)

<u>Initial:</u>        0.0280        0.0120

<u>At eqllm:</u>    0.0280-4x   0.0120-3x   2x       6x

We are given:

Equilibrium concentration of nitrogen gas = 3.00\times 10^{-3}M=0.003

Evaluating the value of 'x', we get:

\Rightarrow 2x=0.003\\\\\Rightarrow x=0.0015M

Now, equilibrium concentration of ammonia = 0.0280-4x=[0.0280-(4\times 0.0015)]=0.022M

Equilibrium concentration of oxygen gas = 0.0120-3x=[0.0120-(3\times 0.0015)]=0.0075M

Equilibrium concentration of water = 6x=(6\times 0.0015)]=0.009M

The expression of K_{eq} for the above reaction follows:

K_{eq}=\frac{[H_2O]^6\times [N_2]^2}{[NH_3]^4\times [O_2]^3}

Putting values in above expression, we get:

K_{eq}=\frac{(0.009)^6\times (0.003)^2}{(0.022)^4\times (0.0075)^3}\\\\K_{eq}=4.84\times 10^{-5}

Hence, the value of K_{eq} is 4.84\times 10^{-5}

4 0
3 years ago
A. 207 kJ<br> B. 4730 kJ<br> O C. 9460 kJ<br> O D. 414 kJ
slavikrds [6]

Answer:

C = 9460 Kj

Explanation:

Given data:

Mass of copper = 2kg

Latent heat of vaporization = 4730 Kj/Kg

Energy required to vaporize 2kg copper = ?

Solution:

Equation

Q= mLvap

by putting values,

Q= 2kg ×  4730 Kj/Kg

Q = 9460 Kj

3 0
3 years ago
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