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jonny [76]
2 years ago
11

HELP

Chemistry
1 answer:
Wittaler [7]2 years ago
8 0

Answer:

Explanation:

1.

 Given parameters:

Number of moles of CaO = 0.22moles

Unknown:

Mass of CaO = ?

Solution:

Mass, number of moles and molar mass are related using the expression below;

  Mass  = number of moles x molar mass

Molar mass of CaO  = 40 + 16  = 56g/mol

  Insert the parameters and solve;

  Mass = 0.22 x 56  = 12.32g

2

Given parameters:

Number of moles of NaCl  = 0.83moles

Unknown:

mass of NaCl  = ?

Solution:

Also,

 Mass  = number of moles x molar mass

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Now insert the parameters and solve;

    mass = 0.83 x 58.5

     mass  = 48.6g

3.

Given parameters:

Number of moles of H₂SO₄  = 0.5moles

Unknown:

mass of H₂SO₄ = ?

Solution:

Mass  = number of moles x molar mass

Molar mass of H₂SO₄  = 2(1) + 32 + 4(16) = 98g/mol

Insert the parameters and solve;

  Mass = 0.5 x 98  = 49g

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Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
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<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

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[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

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