All categories

2 years ago

What does AS<0 mean in a reaction?

1 answer:

5 0

I don't know exactly but you can try narrowing down your answers down to A or D but it might be D if the system is random if that even helps and makes sense-

You might be interested in

The sum of the first 10 terms of an arithmetic progression is 120 and the sum of first twenty is 840. find sum of first 30 terms

STatiana [176]

Answer:

The sum of first 30 terms of the arithmetic progression is 2160.

Explanation:

For an arithmetic progression, the sum of first $n$ terms with first term as $a$ and common difference $d$ is given as:

$S_n=\frac{n}{2}(2a+(n-1)d)$

Now, it is given that:

$For\ n=10,S_n=120\\For\ n=20,S_n=840$

Now, plug in these values and frame two equations in $a\ and\ d$

$S_{10}=\frac{10}{2}(2a+(10-1)d)\\120=5(2a+9d)\\2a+9d=\frac{120}{5}\\2a+9d=24------------1$

$S_{20}=\frac{20}{2}(2a+(20-1)d)\\840=10(2a+19d)\\2a+19d=\frac{840}{10}\\2a+19d=84-----------2$

Now, we solve equations (1) and (2) for $a\ and\ d$ . Subtract equation (1) from equation (2). This gives,

$2a+19d-2a-9d=84-24\\19d-9d=60\\10d=60\\d=\frac{60}{10}=6$

Now, plug in the value of $d=6$ in equation (1) and solve for $a$ .

$2a+9(6)=24\\2a+54=24\\2a=24-54\\2a=-30\\a=\frac{-30}{2}=-15$

Plug in the values of $a=-15,\ n=30\ and\ d=6$ in the sum formula to find the sum of first 30 terms.

Now, the sum of first 30 terms is given as:

$S_{30}=\frac{30}{2}(2(-15)+(30-1)(6))\\S_{30}=15(-30+29(6))\\S_{30}=15(-30+174)\\S_{30}=15(144)=2160$

Therefore, the sum of first 30 terms of the arithmetic progression is 2160.

4 0

3 years ago

Which is another word for 10 meters in the metric system?

kotegsom [21]

Answer:

Dekameter

Explanation:

8 0

3 years ago

An old 0.500 L lecture bottle of triethylamine (N(CH₂CH₃)₃) was found in a lab and needed for a synthesis reaction. A pressure r

Tatiana [17]

Mass of vaporized triethylamine : 2.606 g

<h3>Further explanation</h3>

Given

0.5 L triethylamine

P = 18.5 psi

T = 25 °C

Required

mass of vaporized triethylamine

Solution

Conversion :

P 18.5 psi = 1,26 atm

T = 25 +273 = 298 K

Ideal gas law :

PV=nRT

n = PV/RT

Input the value :

n = (1.26 atm x 0.5 L) /(0.08205 x 298)

n = 0.0258

MW triethylamine = 101 g/mol

Mass triethylamine :

= n x MW

= 0.0258 x 101 g/mol

= 2.606 g

6 0

3 years ago

How many grams of solid Na2CO3 are required to neutralize exactly 2 liters of an HCI solution of pH 2.0?

Snezhnost [94]

Answer:

The answer is 1.06g.

Explanation:

Analysis of question:

1. Identify the information in the question given.

volume of HCl is 2 dm3
pH of HCl is 2.0

2. What the question want?

mass of Na2CO3 is ?(unknown)
3. Do calculation.
1st-Write a balanced chemical equation:

Na2CO3 + 2HCl (arrow) 2NaCl + H20 + CO2

2nd-Determine the molarity of HCl with the value of 2.0.

pH= -log[H+]

2.0= -log[H+]

log[H+]= -2.0

[H+]= 10 to the power of negative 2(10-2)

=0.01 mol dm-3

molarity of HCl is 0.01 mol dm-3

3rd-Find the number of moles of HCl

n=MV

=0.01 mol dm-3 × 2 dm3

=0.02 mol of HCl

4th-Find the second mol of it.

Based on the chemical equation,

2.0 mol of HCl reacts with 1.0 mol of Na2CO3

0.02 mol of HCl reacts with 0.01 mol of Na2CO3

Na2CO3>a=1 mol

2HCl>b=2 mol

5th-Find the mass of it.

mass= number of mole × molar mass

g=0.01 × [2(23)+ 12+ 3(16)]

g=0.01 × 106

# =1.06 g.

3 0

3 years ago

Which of the following describes a reaction that reaches equilibrium?

alexandr1967 [171]

Answer:The product and reactants reach a final, unchanging level.

8 0

3 years ago