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Over [174]
3 years ago
15

Which of the following describes a reaction that reaches equilibrium?

Chemistry
1 answer:
alexandr1967 [171]3 years ago
8 0

Answer:The product and reactants reach a final, unchanging level.

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Fill in the blank Cells break down sugar and release ___________ into the plant.
katrin2010 [14]

Answer:

oxygen

Explanation:

8 0
2 years ago
Could someone help me with this?
Varvara68 [4.7K]

Solving part-1 only

#1

KMnO_4

  • Transition metal is Manganese (Mn)

#2

Actually it's the oxidation number of Mn

Let's find how?

\\ \tt\Rrightarrow x+1+4(-2)=0

\\ \tt\Rrightarrow x+1-8=0

\\ \tt\Rrightarrow x-7=0

\\ \tt\Rrightarrow x=+7

  • x is the oxidation number

#3

  • Purple as per the color of potassium permanganate

#4

\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}

7 0
2 years ago
Can mercury turn on a light?
PilotLPTM [1.2K]

Answer:

Mercury is useful in lighting because it contributes to the bulbs' efficient operation and life expectancy. Fluorescent and other mercury-added bulbs are generally more energy efficient and last longer than incandescent and other equivalent forms of lighting.

Explanation:

3 0
3 years ago
Calculate the moles and grams of solute in 2.0 L of 0.30M Na SO..
Ostrovityanka [42]

Answer:

Number of moles of solute = 0.6 mole

Mass =13.8 g

Explanation:

Given data:

Number of moles of sodium = ?

Volume = 2.0 L

Molarity = 0.30 M

Mass in gram of sodium= ?

Solution:

<em>Number of moles:</em>

Molarity = number of moles of solute / volume in litter

Number of moles of solute = Molarity × volume in litter

Number of moles of solute = 0.30 M × 2.0 L

Number of moles of solute = 0.6 mole

<em>Mass in gram:</em>

Mass = Number of moles × molar mass

Mass = 0.6 mole× 23 g/mol

Mass =13.8 g

3 0
3 years ago
Plz help asap What can you conclude about the iron(ii) and iron(iii) ions?
zavuch27 [327]

Answer:

The chemistry of iron is dominated by the +2 and +3 oxidation states i.e. iron(II) and iron(III) complexes e.g. Fe2+ and Fe3+ complex ions with selected ligands, usually of an octahedral shape, a few tetrahedral iron(III) complexes are mentioned too. The reactions of the aqueous ions iron(II) and iron(III) with ammonia, sodium hydroxide and sodium carbonate are described and explained as are complexes of iron(III) with the chloride ion and cyanide ion.

principal oxidation states of iron, redox reactions of iron, ligand substitution displacement reactions of iron, balanced equations of iron chemistry, formula of iron complex ions, shapes colours of iron complexes, formula of compoundsExplanation:

5 0
2 years ago
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