Answer:
A) homotopic and B) enantiotopic
Explanation:
Protons chemically equivalent are those that have the same chemical shift, also if they are interchangeable by some symmetry operation or by a rapid chemical process.
The existence of symmetry axes, Cn, that relate to the protons results in the protons being homotopic, that is chemically equivalent in both chiral and aquiral environments.
The existence of a plane of symmetry, σ, makes the protons related by it, are enantiotopic and these protons will only be equivalent in an aquiral medium; if the medium is chiral both protons will be chemically NOT equivalent. The existence of a center of symmetry, i, in the molecule makes the related protons through it enantiotopic and therefore chemically only in the aquiral medium.
Diastereotopic protons cannot be interconverted by any symmetry operation and they are different, with different chemical displacement.
1550J
Explanation:
Given parameters:
Heat of fusion = 155J/g
Mass of sample = 10g
Unknown:
Quantity of heat removed to freeze the substance =?
Solution:
This is a phase change problem and we apply the formula for the specific heat of fusion to solve the problem:
Q = mL
m is the mass of the substance
L is the specific heat of fusion of the substance.
We then plug the parameters into the equation:
Q = 155J/g x 10g = 1550J
Learn more:
specific heat brainly.com/question/7210400
#learnwithBrainly
For this problem, we use the Faradays law to relate the mass electroplated and the current passed through. We do as follows:
60.1 g (1 mol / 196.67 g) (1 mol e- / 1 mol Au) ( 96500 C / 1 mol e- ) = 29486.25 C
Q = It
29486.25 = 5t
t = 5897.85 s = 98.30 min
Hope this answers the question.
They contain both carbon and hydrogen :)
a. 30 moles of H₂O
b. 2.33 moles of N₂
<h3>Further explanation</h3>
Given
a. 20 moles of NH₃
b. 3.5 moles of O₂
Required
a. moles of H₂O
b. moles of N₂
Solution
Reaction
4NH₃+3O₂⇒2N₂+6H₂O
a. From the equation, mol ratio NH₃ : H₂O = 4 : 6, so mol H₂O :
=6/4 x mol NH₃
= 6/4 x 20 moles
= 30 moles
b. From the equation, mol ratio N₂ : O₂ = 2 : 3, so mol N₂ :
=2/3 x mol O₂
= 2/3 x 3.5 moles
= 2.33 moles