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meriva
3 years ago
7

30 points please help

Chemistry
1 answer:
postnew [5]3 years ago
4 0

Answer:

its D I'm pretty sure because it's from high heat/pressure

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10.0 mL of 0.0400 M KBrO3 and 10.0 mL 0.100 M HCl is mixed with 10.0 mL of 0.0100 M KI, 10.0 mL 0.00100 M Na2S2O3, 1.0 mL of sta
Oliga [24]

Answer:

0.0196

Explanation:

The Total volume of the solution = Volume of (KBrO_3 + HCl + KI +Na_2S_2O_3 + Starch + H_2O)

= 10 mL + 10 mL + 10 mL+ 10 mL + 1 mL + 10 mL

= 51 mL

The concentration of  [H^+] = \dfrac{ mL \ used \times 0.1 \ M}{total \ volume}

= \dfrac{10 \ mL \times 0.1 M}{51 \ mL}

= 0.0196

5 0
3 years ago
What is the fully balanced equation of( strontium thiocyanate plus potassium yield) I need the fully balanced equation and produ
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A fully balanced equation of strontium thiocyanate plus potassium yields an aqueous solution of iron (III) thiocyanate and potassium nitrate. ( I think it's : Fe(NO3)3 (aq) + KSCN (aq)


Answer: Iron thiocyanate and potassium nitrate


Look on google, cheg. com maybe



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4 0
3 years ago
Which of the following explains the importance of the activation energy acting as a barrier for reactants? A:It prevents most re
natita [175]
A: It prevents most reactions from occurring spontaneously.

The answer above is correct.
7 0
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What happens to Kinetic?<br> energy during gas particles collision
Vitek1552 [10]

Answer:

Gas particles are in a constant state of the  random motion and move in straight lines until they collide with another body. The collisions exhibited by gas particles are completely elastic; when the two molecules collide, total kinetic energy is conserved.

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4 years ago
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the specific heat of the metallic element rhodium is 0.240 j/g-k at 25°c. if 586 j of heat is added to an 80.0 g block of rhodiu
andrey2020 [161]

The expected final temperature of the block, given that 586 J of heat were added to it is 55.5 °C

<h3>How to determine the final temeprature</h3>

We'll begin by obtaining the change in the temperature of the block. This can be obtained as follow:

  • Specific heat capacity of block (C) = 0.240 J/gºC
  • Heat added (Q) = 586 J
  • Mass of block (M) = 80.0 g
  • Change in temperature (ΔT) =?

Q = MCΔT

Divide both sides by MC

ΔT = Q / MC

ΔT = 586 / (80.0 × 0.240)

ΔT = 586 / 19.2

ΔT = 30.5 °C

Finally, we shall determine the final temperature of the block. This can be obtained as follow:

  • Initial temperature (T₁) = 25 °C
  • Change in temperature (ΔT) = 30.5 °C
  • Final temperature (T₂) = ?

ΔT = T₂ – T₁

30.5 = T₂ – 25

Collect like terms

T₂ = 30.5 + 25

T₂ = 55.5 °C

Thus, from the calculation made above, we can conclude that the final temperature is 55.5 °C

Learn more about heat transfer:

brainly.com/question/14383794

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6 0
1 year ago
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