Answer:
0.0196
Explanation:
The Total volume of the solution = Volume of 
= 10 mL + 10 mL + 10 mL+ 10 mL + 1 mL + 10 mL
= 51 mL
The concentration of ![[H^+] = \dfrac{ mL \ used \times 0.1 \ M}{total \ volume}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%20%3D%20%5Cdfrac%7B%20mL%20%5C%20used%20%5Ctimes%200.1%20%5C%20M%7D%7Btotal%20%5C%20volume%7D)
= 0.0196
A fully balanced equation of strontium thiocyanate plus potassium yields an aqueous solution of iron (III) thiocyanate and potassium nitrate. ( I think it's : Fe(NO3)3 (aq) + KSCN (aq)
Answer: Iron thiocyanate and potassium nitrate
Look on google, cheg. com maybe
live
A: It prevents most reactions from occurring spontaneously.
The answer above is correct.
Answer:
Gas particles are in a constant state of the random motion and move in straight lines until they collide with another body. The collisions exhibited by gas particles are completely elastic; when the two molecules collide, total kinetic energy is conserved.
Hope it helps!
The expected final temperature of the block, given that 586 J of heat were added to it is 55.5 °C
<h3>How to determine the final temeprature</h3>
We'll begin by obtaining the change in the temperature of the block. This can be obtained as follow:
- Specific heat capacity of block (C) = 0.240 J/gºC
- Heat added (Q) = 586 J
- Mass of block (M) = 80.0 g
- Change in temperature (ΔT) =?
Q = MCΔT
Divide both sides by MC
ΔT = Q / MC
ΔT = 586 / (80.0 × 0.240)
ΔT = 586 / 19.2
ΔT = 30.5 °C
Finally, we shall determine the final temperature of the block. This can be obtained as follow:
- Initial temperature (T₁) = 25 °C
- Change in temperature (ΔT) = 30.5 °C
- Final temperature (T₂) = ?
ΔT = T₂ – T₁
30.5 = T₂ – 25
Collect like terms
T₂ = 30.5 + 25
T₂ = 55.5 °C
Thus, from the calculation made above, we can conclude that the final temperature is 55.5 °C
Learn more about heat transfer:
brainly.com/question/14383794
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