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natta225 [31]
3 years ago
9

Calculate the mass percent by volume of 330.1 g of glucose (C₆H₁₂O₆, MM = 180.2 g/mol) in 325 mL of solution.

Chemistry
1 answer:
nadezda [96]3 years ago
3 0

Answer: The mass percent by volume is 101.6%

Explanation:

The solution concentration expressed in percent by volume means that the amount of solute present in 100 parts volume of solution.

It is represented in formula as :

mass percent by volume =\frac{\text {mass of solute}\times 100}{\text {Volume of solution in ml}}\%

Given : mass of glucose = 330.1 g

volume of solution = 325 ml

Thus mass percent by volume =\frac{330.1g\times 100}{325ml}=101.6\%

Thus the mass percent by volume is 101.6%

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Calculate the number of oxygen atoms in a 80.0 g sample of scheelite (CaWo).
castortr0y [4]

Answer:

Explanation:

scheelite is CaWO₄

Mol weight = 288

80 g of scheelite = 80 / 288 = 27.77 x 10⁻² moles

27.77 x 10⁻² moles of scheelite = 27.77 x 10⁻² x 6.02 x 10²³  molecules of scheelite

= 167.17 x 10²¹ molecules of scheelite

1 molecule of scheelite contains 4 atoms of oxygen

167.77 x 10²¹ molecules of scheelite contains 4 x 167.77 x 10²¹ atoms of oxygen .

= 671.08 x 10²¹ atoms of oxygen .

= 671 x 10²¹ atoms .

3 0
3 years ago
Why are fixed resistors’ values indicated by color bands rather than printing the numeric value on their exterior?
gladu [14]
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6 0
3 years ago
What is the chemical formula for nickel (ii) hypochlorite?
gtnhenbr [62]
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3 0
3 years ago
What is the concentration of chloride ion when 16.8ml of a 0.554 M solution of barium chloride is combined with 16.8ml of a 0.59
ozzi

Answer:

The concentration of chloride ion is 2.887 M.

Explanation:

Here we have a combination BaCl₂  and AlCl₃

1 mole BaCl₂ can produce 2 moles chloride ions as follows;

BaCl₂ → Ba²⁺ + 2Cl⁻

Therefore;

0.554  mole BaCl₂ can produce 2×0.554  moles chloride ions;

1 mole AlCl₃ can produce 3 moles chloride ions as follows;

AlCl₃ → Al³⁺ + 3Cl⁻

Therefore;

0.593 mole AlCl₃ can produce 3×0.593 moles chloride ions

Total concentration of chloride ions = 2×0.554 + 3×0.593 = 2.887 moles of Cl⁻ in 2×16.8 ml solution

The concentration of Cl⁻ is 2.887 M

4 0
4 years ago
I need help ASAP! 10 points!
Nina [5.8K]

Answer:

The answer to this question is ( a )

Explanation:

7 0
3 years ago
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