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Talja [164]
2 years ago
11

A bag contains 4 black tiles, 5 white tiles, and 6 blue tiles. Event A is

Mathematics
1 answer:
Murljashka [212]2 years ago
6 0

Answer:

2/21

Step-by-step explanation:

The question is badly formatted so cannot match the answer choice

Total number of tiles = 4 + 5 + 6 = 15

P(A) = P(drawing a black tile from 15 tiles) = 4/15

After event A, there are 14 tiles left : 3 black, + 5 white + 6 blue

P(B/A) = P(drawing white tile after a black tile has been drawn) = 5/14

P(A and B) = P(A).P(B/A) = 4/15 x 5/14 = 2/21

Note that P(B) = 5/15 since we are talking about independently drawing a white tile from the original stack of tiles

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mr Goodwill [35]

Answer: A

Step-by-step explanation:

8 0
2 years ago
One day a store sold 21 sweatshirts. white ones cost​ $9.95 and yellow ones cost $ 11.50. in​ all, ​$235.30 worth of sweatshirts
FromTheMoon [43]
For this problem you have yo set up two equations.

White shirts = w Yellow shirts = y

1st: w + y = 21
2nd: 9.95w + 11.50y = 235.30

Now we're going to do system of equations using substitution.

If w + y = 21, then y = 21 - w
If y = 21 - w, then you can substitute this in the second equation for y.

9.95w + 11.50(21 - w) = 235.30
9.95w + 241.5 - 11.50w = 235.30
-1.55w + 241.5 = 235.30
-1.55w = -6.2
w = 4, so 4 whites shirt were sold.

Now I'm finding out how many yellow shirts were sold using one of the two equations at the top.

w + y = 21
4 + y = 21
y = 17

So 17 yellow shirts were sold and 4 white shirts were sold.
5 0
3 years ago
Which answers choice shows that the set of irrational numbers is not closed under addition?
babunello [35]
Problably A !!!!!!!!!!!
7 0
3 years ago
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Which results only in a horizontal compression of y= 1/х by a factor of 6?
marta [7]

Answer:

I'm assuming you mean a compression of factor 6

In that case, it will be h = 1/6x

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3 years ago
Simplify.<br> 3sqrt -64m^15n^3<br><br> -8m^5<br> -8m^5n<br> -4m^5n<br> -4m^5
makkiz [27]

Answer:

-4m^5n

Step-by-step explanation:

∛-64 = -4

\sqrt[3]{m^{15}} =m^5

∛n³ = <em>n</em>

8 0
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