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Marianna [84]
3 years ago
7

Which answers choice shows that the set of irrational numbers is not closed under addition?

Mathematics
2 answers:
babunello [35]3 years ago
7 0
Problably A !!!!!!!!!!!
denis23 [38]3 years ago
5 0

Answer:

\pi + (-\pi)=0

Step-by-step explanation:

First of all, we have to define what refers "closed under addition".

The closure property under operations is when we operate to number and we get a result that's inside the same number field. For example, if we sum one integer with another one, we would have an integer as a result, that means integers are closed under addition.

So, if you observe the possible answers, you would see that \pi + (-\pi)=0 is not showing closure under addition, because it doesn't result in a irrational as the third choice do \pi + \pi = 2 \pi

Therefore, the answer is the first option.

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