Question

Which answers choice shows that the set of irrational numbers is not closed under addition?

Answer 1

Problably A !!!!!!!!!!!

Answer 2

Answer:

$\pi + (-\pi)=0$

Step-by-step explanation:

First of all, we have to define what refers "closed under addition".

The closure property under operations is when we operate to number and we get a result that's inside the same number field. For example, if we sum one integer with another one, we would have an integer as a result, that means integers are closed under addition.

So, if you observe the possible answers, you would see that $\pi + (-\pi)=0$ is not showing closure under addition, because it doesn't result in a irrational as the third choice do $\pi + \pi = 2 \pi$

Therefore, the answer is the first option.