Which answers choice shows that the set of irrational numbers is not closed under addition?

Mathematics

2 answers:

babunello [35]2 years ago

7 0

Problably A !!!!!!!!!!!

denis23 [38]2 years ago

5 0

Answer:

$\pi + (-\pi)=0$

Step-by-step explanation:

First of all, we have to define what refers "closed under addition".

The closure property under operations is when we operate to number and we get a result that's inside the same number field. For example, if we sum one integer with another one, we would have an integer as a result, that means integers are closed under addition.

So, if you observe the possible answers, you would see that $\pi + (-\pi)=0$ is not showing closure under addition, because it doesn't result in a irrational as the third choice do $\pi + \pi = 2 \pi$

Therefore, the answer is the first option.

You might be interested in

A standard number die is tossed. Find P(4 or even).

zmey [24]

Answer:

50%

Step-by-step explanation:

4 0

3 years ago

Bowl A contains three red and two white chips, and bowl B contains four red and three white chips. A chip is drawn at random fro

____ [38]

$\Large \text {Answer:}$

$\large \boxed {\dfrac{23}{40}}$

$\Large \text {Step-by-step explanation:}$

$\text{P}_{B}(r) = \text{P}_{A}(r) \cdot \text{P}_{B}(r) + \text{P}_{A}(w) \cdot \text{P}_{B}(r)$

$\text{P}_{B}(r) = \left (\dfrac{3}{5} \right ) \negthickspace \left(\dfrac{5}{8}\right ) + \left (\dfrac{2}{5} \right ) \negthickspace \left (\dfrac{4}{8} \right )$