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lakkis [162]
4 years ago
8

Rewrite the quadratic function in standard form and give the vertex f(x)=3x^2-6x-9

Mathematics
1 answer:
pickupchik [31]4 years ago
3 0

Answer:

y=3(x-1)^2-12

Step-by-step explanation:

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6. –9 – 6(w + 5) (1 point) –15w + 5 –15w + 30 –6w – 39 –6w + 21
Oksi-84 [34.3K]

Answer:

-9-6(w+5)=-6w+21

Step-by-step explanation:

We are given expression as

-9-6(w+5)

We are given to simplify it

So, firstly we will distribute -6

and then we can combine like terms

-9-6(w+5)=-9-6\times w-6\times 5

we can multiply it

-9-6(w+5)=-9-6w+30

-9-6(w+5)=30-9-6w

-9-6(w+5)=21-6w

we can also write as

-9-6(w+5)=-6w+21

So, answer is

-9-6(w+5)=-6w+21


5 0
3 years ago
Which of the following is the solution to the inequality below? -3(x-3) > 5 -5x o A. x)-2 O >> c. x D. 2​
Gwar [14]
X>−2, it’s hard to read what your options are, but that’s the answer! Hope this helps !
7 0
3 years ago
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Please help me out i suck at this
Kitty [74]

Answer:

I dont know I just want points

Step-by-step explanation:

7 0
3 years ago
I NEED HELP BAD MATH ASAP
nexus9112 [7]
69.75 - 64.85 = 4.90 or better yet 4.9
8 0
3 years ago
HELP!!!!
Lera25 [3.4K]

Answer:

  • a. the y-intercept of f(x) is greater than the y-intercept of g(x)

Step-by-step explanation:

<u>Given function:</u>

  • f(x)=(x - 4)^2 - 4

<u>We can work out the function from the table values:</u>

  • g(x) = (x + 2)^2 - 4

<u>Options:</u>

a. the y-intercept of f(x) is greater than the y-intercept of g(x)

  • True. x= 0 ⇒ f(0) = (-4)^2 - 4 = 12, g(0) = 2^2 - 4 = 0

b. The y-intercept of g(x) is greater than the y-intercept of f(x)

  • False. See previous option.  

c. The y-coordinate of the vertex of f(x) s greater than the y-coordinate of the vertex of g(x)

  • False. They are same = -4

d. The x-coordinate of the vertex of g(x) is greater than the x-coordinate of the vertex of f(x)

  • False. -2 vs 4
7 0
3 years ago
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