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lakkis [162]
3 years ago
8

Rewrite the quadratic function in standard form and give the vertex f(x)=3x^2-6x-9

Mathematics
1 answer:
pickupchik [31]3 years ago
3 0

Answer:

y=3(x-1)^2-12

Step-by-step explanation:

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Answer:B,C,A,C.

Step-by-step explanation:

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Paul's dad made a turkey pot pie for dinner on Wednesday the family ate 4/8 of the pie. on Thursday after school,Paul ate 2/16 o
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Using the expression 10xy + 6, what are the terms?<br><br> PLEASE HURRY!!
Kaylis [27]

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2 terms.

Step-by-step explanation:

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6 0
3 years ago
The area of a rectangle is 1824 square feet. The length is 48 feet. What s the width?
Naddika [18.5K]

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6 0
3 years ago
Those are not the powers question from transformation of product and sum trigonometry
OlgaM077 [116]

Answer:

see explanation

Step-by-step explanation:

Using the sum to product identity

cosx + cosy = 2cos(\frac{x+y}{2} )cos( \frac{x-y}{2} )

Consider left side

(cos5A +cos3A) + (cos15A + cos7A)

= 2cos(\frac{5A+3A}{2} )cos(\frac{5A-3A}{2} ) + 2cos( \frac{15A+7A}{2}) cos( \frac{15A-7A}{2} )

= 2cos(\frac{8A}{2}) cos(\frac{2A}{2}) + 2cos(\frac{22A}{2} )cos(\frac{8A}{2} )

= 2cos4AcosA + 2cos11A cos4A ← factor out 2cos4A from both terms

= 2cos4A( cos11A + cosA) ← repeat the process

= 2cos4A( 2cos(\frac{11A+A}{2} )cos(\frac{11A-A}{2} )

= 2cos4A(2cos(\frac{12A}{2})cos(\frac{10A}{2} )

= 2cos4A(2cos6A cos5A)

= 4cos4Acos5Acos6A

= right side , thus verified

8 0
2 years ago
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