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maw [93]
2 years ago
15

The speed of light in a vacuum is 29,980,000,000

Mathematics
2 answers:
Flura [38]2 years ago
6 0

Answer:

<u>B. 2.998 x 10¹⁰</u>

Step-by-step explanation:

Given :

  • 29,980,000,000

Steps in solving :

  1. Take the zeros after the last non-zero digit as a power of 10.
  2. Take the non-zero part (in the part) and put a decimal point after between the thousands and hundreds place, and shift the remaining powers of 10 to the previously grouped part.
  3. Adjust further if needed to match an answer.

Solving :

  • 29,980,000,000
  • 2,998 x 10⁷
  • 2.998 x 10³ x 10⁷
  • <u>2.998 x 10¹⁰</u>
sweet [91]2 years ago
4 0

Answer:

\huge\boxed{\sf 2.998 \times  10^{10}}

Step-by-step explanation:

<u>Given number:</u>

29,980,000,000

<u>Rules:</u>

  • Move the decimal point after the first non-zero digit. (after 2)
  • Here, we will move the decimal point 10 places to the left to move it after the first non-zero digit.
  • Since we move the decimal point 10 places, we will write the number as a multiple of 10¹⁰ (10 being the exponent).

<u>The number will become:</u>

2.998 × 10¹⁰

\rule[225]{225}{2}

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Tanzania [10]

Answer:

 |x − 0.5| = 0.05

Step-by-step explanation:

Here x represents the diameter,

Since, an error of 0.05 millimeters is allowance in diameter,

Thus, the maximum acceptable diameter = x + 0.05,

And, the minimum acceptable diameter = x - 0.05

According to the question,

The holes will have a diameter of 0.5 millimeters,

Thus, x - 0.05 < 0.5  and 0.5 < x + 0.05

⇒ x - 0.5 < 0.05 and x - 0.5 > - 0.05  

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⇒ |x-0.5| < 0.05

⇒ Option D is correct.

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3 years ago
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IRISSAK [1]

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3 years ago
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joja [24]

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2 years ago
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URGENT!!!! The area of a rectangular floor is 80 square feet. The length of the floor is 2 feet less than the width of the floor
KatRina [158]

Answer:

The width of the floor is 10 ft.

Step-by-step explanation:

First, you have to form expressions of width and length in terms of w. With the given information :

width = w ft

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Given that the area of rectange is A = length × width so you have to subtitute the expressions and value into the formula :

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3 years ago
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