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Aloiza [94]
2 years ago
5

Robin has 10 books. There is enough space on a shelf for 4 books. In how many ways can 4 of the 10 books be

Mathematics
1 answer:
aliina [53]2 years ago
8 0

The number of arrangements of the books is an illustration of permutation

The books can be arranged in 5040 ways

<h3>How to determine the number of arrangements?</h3>

The given parameters are:

  • Total books, n = 10
  • Books to arrange, r = 4

The number of arrangements is calculated as:

Ways = nPr

Substitute the given values

Ways = ¹⁰P₄

Apply the permutation formula

Ways = 10!/(10 - 4)!

Evaluate the quotient

Ways = 5040

Hence, the books can be arranged in 5040 ways

Read more about permutation at:

brainly.com/question/12468032

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4 packs of invitations and 2 packs of napkins.

Step-by-step explanation:

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3 years ago
Which of the following best represents the highest potential for nonresponse bias in a sampling strategy? Describe why this opti
natta225 [31]

Answer:

c. Asking people leaving a local election to take part in an exit poll

Step-by-step explanation:

Asking people leaving a local election to take part in an exit poll best represents the highest potential for nonresponse bias in a sampling strategy because of the importance of the local election compared to the exit polls.

It is worthy of note that nonresponse bias occurs when some respondents included in the sample do not respond to the survey. The major difference here is that the error comes from an absence of respondents not the collection of erroneous data. ...

Oftentimes, this form of bias is created by refusals to participate for one reason or another or the inability to reach some respondents.

7 0
3 years ago
Pleaseee helppp answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!!!
Aloiza [94]
Srry im late it’s 8 mark Brainly ist
3 0
3 years ago
A rhombus has a base of 5.2 meters and a height of 4.5 meters. The rhombus is divided into two identical triangles. What is the
Lisa [10]

Answer:

11.7 m²

Step-by-step explanation:

What is the area of each triangle ?

A = b×h/2

= 5.2m×4.5m/2

= 23.4m²/2

= 11.7 m²

3 0
3 years ago
Samples of rejuvenated mitochondria are mutated(defective) in 1% ofcases. Suppose 15 samples are studied, and they can be consid
Bezzdna [24]

Answer:

A)0.86

B)0.99

C)6.047E-13

Step-by-step explanation:

Since p = 0.01 and q= 0.99

Number of event n = 15

Using binomial expansion

A) Probability (No samples are mutated) = 15C0 (p)^0 * (q)^15

= 1*(0.01)^0*(0.99)^15 = 0.86

B)Probability (At most one sample is mutated) = 15C0 * p^0 *q^15 + 15C1 * p^1 * q^14 = 1*(0.01)^0*(0.99)^15 + 15C1 * 0.01 * 0.99^14 = 0.86 + 15*0.01*0.8687 = 0.86 + 0.13 = 0.99

C) Probability (More than half the samples are mutated) = 15C8* 0.01^8 * 0.99^7 + 15C9* 0.01^9 * 0.99^6 +15C10* 0.01^10 *0.99^5 + 15C11 * 0.01^11 * 0.99^4 + 15C12 * 0.01^12 * 0.99^3 + 15C13 * 0.01^13 * 0.99^ 2 + 15C14 * 0.01^14 * 0.99^1 + 15C15 * 0.01^15 * 0.99^0

Probability (More than half the samples are mutated) = 6E-13 + 4.71E-15 + 2.86E-17 + 1.31E-19 + 4.41E-22 + 1.03E-24 + 1.49E-27 + 1E-30 = 6.047E-13

3 0
3 years ago
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